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authorDave Jacoby <jacoby.david@gmail.com>2024-09-18 19:56:42 -0400
committerDave Jacoby <jacoby.david@gmail.com>2024-09-18 19:56:42 -0400
commitf86f5e2fec16020c1d86f9028fb0f61cfeac106e (patch)
tree0fd388a696b51ffde5a7bfe8519a74e1caf42461 /challenge-060/paulo-custodio/python
parentff8719c86653d5ad3121955e9494a0010527c2b9 (diff)
parent0052ec63ca70eaa6d9ffb1926c294dbfd85f8c05 (diff)
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Merge branch 'master' of https://github.com/manwar/perlweeklychallenge-club
Diffstat (limited to 'challenge-060/paulo-custodio/python')
-rw-r--r--challenge-060/paulo-custodio/python/ch-1.py43
-rw-r--r--challenge-060/paulo-custodio/python/ch-2.py50
2 files changed, 93 insertions, 0 deletions
diff --git a/challenge-060/paulo-custodio/python/ch-1.py b/challenge-060/paulo-custodio/python/ch-1.py
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+++ b/challenge-060/paulo-custodio/python/ch-1.py
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+#!/usr/bin/env python3
+
+# Challenge 060
+#
+# TASK #1 > Excel Column
+# Reviewed by: Ryan Thompson
+# Write a script that accepts a number and returns the Excel Column Name it
+# represents and vice-versa.
+#
+# Excel columns start at A and increase lexicographically using the 26 letters
+# of the English alphabet, A..Z. After Z, the columns pick up an extra "digit",
+# going from AA, AB, etc., which could (in theory) continue to an arbitrary
+# number of digits. In practice, Excel sheets are limited to 16,384 columns.
+#
+# Example
+# Input Number: 28
+# Output: AB
+#
+# Input Column Name: AD
+# Output: 30
+
+import re
+import sys
+
+def col2num(col):
+ num = 0
+ for digit in col:
+ num = 26*num + ord(digit)-ord('A') + 1
+ return num
+
+def num2col(num):
+ col = ""
+ while num > 0:
+ digit = (num-1) % 26
+ num = int((num-1) / 26)
+ col = chr(ord('A')+digit) + col
+ return col
+
+arg = sys.argv[1]
+if re.search(r'^\d+$', arg):
+ print(num2col(int(arg)))
+else:
+ print(col2num(arg))
diff --git a/challenge-060/paulo-custodio/python/ch-2.py b/challenge-060/paulo-custodio/python/ch-2.py
new file mode 100644
index 0000000000..5a159ce266
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+++ b/challenge-060/paulo-custodio/python/ch-2.py
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+#!/usr/bin/env python3
+
+# Challenge 060
+#
+# TASK #2 > Find Numbers
+# Reviewed by: Ryan Thompson
+# Write a script that accepts list of positive numbers (@L) and two positive
+# numbers $X and $Y.
+#
+# The script should print all possible numbers made by concatenating the numbers
+# from @L, whose length is exactly $X but value is less than $Y.
+#
+# Example
+# Input:
+#
+# @L = (0, 1, 2, 5);
+# $X = 2;
+# $Y = 21;
+# Output:
+#
+# 10, 11, 12, 15, 20
+
+import sys
+
+def combine1(combin, prefix, n, digits):
+ if len(prefix) == n:
+ num = int(prefix)
+ if not num in combin:
+ combin.add(num)
+ else:
+ for digit in digits:
+ combine1(combin, prefix+digit, n, digits)
+
+def combine(digits):
+ combin = set()
+ for n in range(1, len(digits)+1):
+ combine1(combin, "", n, digits)
+ nums = sorted(list(combin))
+ return nums
+
+def numbers(X, Y, L):
+ nums = combine(L)
+ nums = list(filter(lambda x:len(str(x))==X and x<Y, nums))
+ return nums
+
+X = int(sys.argv[1])
+Y = int(sys.argv[2])
+L = sys.argv[3:]
+nums = numbers(X, Y, L)
+print(", ".join(map(str, nums)))