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authorDave Jacoby <jacoby.david@gmail.com>2024-09-18 19:56:42 -0400
committerDave Jacoby <jacoby.david@gmail.com>2024-09-18 19:56:42 -0400
commitf86f5e2fec16020c1d86f9028fb0f61cfeac106e (patch)
tree0fd388a696b51ffde5a7bfe8519a74e1caf42461 /challenge-061/paulo-custodio/python/ch-1.py
parentff8719c86653d5ad3121955e9494a0010527c2b9 (diff)
parent0052ec63ca70eaa6d9ffb1926c294dbfd85f8c05 (diff)
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Merge branch 'master' of https://github.com/manwar/perlweeklychallenge-club
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+#!/usr/bin/env perl
+
+# Challenge 061
+#
+# TASK #1 > Product SubArray
+# Reviewed by: Ryan Thompson
+# Given a list of 4 or more numbers, write a script to find the contiguous
+# sublist that has the maximum product. The length of the sublist is irrelevant;
+# your job is to maximize the product.
+#
+# Example
+# Input: [ 2, 5, -1, 3 ]
+#
+# Output: [ 2, 5 ] which gives maximum product 10.
+
+import sys
+
+def product(nums):
+ prod = 1
+ for x in nums:
+ prod *= x
+ return x
+
+
+n = list(map(int, sys.argv[1:]))
+max_sublist = []
+max_prod = int(-1e6)
+
+for i in range(0, len(n)):
+ for j in range(i, len(n)):
+ sublist = n[i:j+1]
+ prod = product(sublist)
+ if prod > max_prod:
+ max_sublist, max_prod = sublist, prod
+
+print(", ".join(list(map(str, max_sublist))))