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| author | 冯昶 <seaker@qq.com> | 2021-03-15 18:13:51 +0800 |
|---|---|---|
| committer | 冯昶 <seaker@qq.com> | 2021-03-15 18:13:51 +0800 |
| commit | 8b6be37fe4dac8b4c6489a95e55514b76b298d15 (patch) | |
| tree | ae36c8ec2c71f606c0e36adaa19dba366a68a0b4 /challenge-099/paulo-custodio/python | |
| parent | 865acfd056fb6f409ec6b1a81d60b931cbcb69fe (diff) | |
| parent | c9aec2da6bcb04b488183f09ca94bee488557aff (diff) | |
| download | perlweeklychallenge-club-8b6be37fe4dac8b4c6489a95e55514b76b298d15.tar.gz perlweeklychallenge-club-8b6be37fe4dac8b4c6489a95e55514b76b298d15.tar.bz2 perlweeklychallenge-club-8b6be37fe4dac8b4c6489a95e55514b76b298d15.zip | |
Merge branch 'master' of github.com:seaker/perlweeklychallenge-club
Diffstat (limited to 'challenge-099/paulo-custodio/python')
| -rw-r--r-- | challenge-099/paulo-custodio/python/ch-1.py | 55 | ||||
| -rw-r--r-- | challenge-099/paulo-custodio/python/ch-2.py | 43 |
2 files changed, 98 insertions, 0 deletions
diff --git a/challenge-099/paulo-custodio/python/ch-1.py b/challenge-099/paulo-custodio/python/ch-1.py new file mode 100644 index 0000000000..4516a3254f --- /dev/null +++ b/challenge-099/paulo-custodio/python/ch-1.py @@ -0,0 +1,55 @@ +#!/usr/bin/env python + +# Challenge 099 +# +# TASK #1 > Pattern Match +# Submitted by: Mohammad S Anwar +# You are given a string $S and a pattern $P. +# +# Write a script to check if given pattern validate the entire string. +# Print 1 if pass otherwise 0. +# +# The patterns can also have the following characters: +# +# ? - Match any single character. +# * - Match any sequence of characters. +# Example 1: +# Input: $S = "abcde" $P = "a*e" +# Output: 1 +# Example 2: +# Input: $S = "abcde" $P = "a*d" +# Output: 0 +# Example 3: +# Input: $S = "abcde" $P = "?b*d" +# Output: 0 +# Example 4: +# Input: $S = "abcde" $P = "a*c?e" +# Output: 1 + +import sys + +def match(s, p): + while True: + if s=="" and p=="": + return True + elif s=="" or p=="": + return False + elif p[0]=="?": + s=s[1:] + p=p[1:] + elif p[0]=="*": + p=p[1:] + for i in range(0, len(s)): + if match(s[i:], p): + return True + return False + elif s[0]!=p[0]: + return False + else: + s=s[1:] + p=p[1:] + +if match(sys.argv[1], sys.argv[2]): + print(1) +else: + print(0) diff --git a/challenge-099/paulo-custodio/python/ch-2.py b/challenge-099/paulo-custodio/python/ch-2.py new file mode 100644 index 0000000000..e82e57f635 --- /dev/null +++ b/challenge-099/paulo-custodio/python/ch-2.py @@ -0,0 +1,43 @@ +#!/usr/bin/env python + +# Challenge 099 +# +# TASK #2 > Unique Sub-sequence +# Submitted by : Mohammad S Anwar +# You are given two strings $S and $T. +# +# Write a script to find out count of different unique sub-sequences matching +# $T without changing the position of characters. +# +# Example 1: +# Input : $S = "littleit', $T = 'lit' +# Output : 5 +# +# 1: [lit] tleit +# 2: [li] t[t] leit +# 3: [li] ttlei[t] +# 4: litt[l] e[it] +# 5: [l] ittle[it] +# Example 2: +# Input : $S = "london', $T = 'lon' +# Output : 3 +# +# 1: [lon] don +# 2: [lo] ndo[n] +# 3: [l] ond[on] + +import sys + +def count_subsequences(s, t): + while True: + if t=="": + return 1 + elif s=="": + return 0 + elif s[0]==t[0]: + return (count_subsequences(s[1:], t[1:]) + + count_subsequences(s[1:], t)) + else: + s=s[1:] + +print(count_subsequences(sys.argv[1], sys.argv[2])) |
