Add Basic, C and C++ solutions to challenge 102

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+/*
+Challenge 102
+
+TASK #2 › Hash-counting String
+Submitted by: Stuart Little
+
+You are given a positive integer $N.
+
+Write a script to produce Hash-counting string of that length.
+
+The definition of a hash-counting string is as follows:
+- the string consists only of digits 0-9 and hashes, ‘#’
+- there are no two consecutive hashes: ‘##’ does not appear in your string
+- the last character is a hash
+- the number immediately preceding each hash (if it exists) is the position
+of that hash in the string, with the position being counted up from 1
+
+It can be shown that for every positive integer N there is exactly one such
+length-N string.
+Examples:
+
+(a) "#" is the counting string of length 1
+(b) "2#" is the counting string of length 2
+(c) "#3#" is the string of length 3
+(d) "#3#5#7#10#" is the string of length 10
+(e) "2#4#6#8#11#14#" is the string of length 14
+*/
+
+#include <iostream>
+#include <string>
+
+std::string hash_count(int n) {
+    std::string str(n, ' ');
+    int i = n - 1;
+    while (i >= 0) {
+        int pos = i + 1;
+        str[i--] = '#';
+        while (i >= 0 && pos != 0) {
+            str[i--] = '0' + (pos % 10);
+            pos /= 10;
+        }
+    }
+    return str;
+}
+
+
+int main(int argc, char* argv[]) {
+    if (argc != 2) {
+        std::cerr << "Usage: ch-1 N" << std::endl;
+        return EXIT_FAILURE;
+    }
+    else 
+        std::cout << hash_count(atoi(argv[1])) << std::endl;
+}