Lua solution for week 111, part 1

2 files changed, 34 insertions, 0 deletions

diff --git a/challenge-111/abigail/README.md b/challenge-111/abigail/README.md
index 92fe052262..bd9ef31d26 100644
--- a/challenge-111/abigail/README.md
+++ b/challenge-111/abigail/README.md
@@ -34,6 +34,7 @@ languages, the fact input is sorted does not offer additional benefits.
 * [AWK](awk/ch-1.awk)
 * [Bash](bash/ch-1.sh)
 * [C](c/ch-1.c)
+* [Lua](lua/ch-1.lua)
 * [Perl](perl/ch-1.pl)
 
 ### Blog
diff --git a/challenge-111/abigail/lua/ch-1.lua b/challenge-111/abigail/lua/ch-1.lua
new file mode 100644
index 0000000000..194e55b458
--- /dev/null
+++ b/challenge-111/abigail/lua/ch-1.lua
@@ -0,0 +1,33 @@
+#!/opt/local/bin/lua
+
+--
+-- See ../README.md
+--
+
+--
+-- Run as: lua ch-1.lua < input-file
+--
+
+local MATRIX_SIZE = 5
+
+matrix = {}
+
+-- 
+-- Read in the matrix
+--
+for i = 1, MATRIX_SIZE * MATRIX_SIZE do 
+    matrix [io . read ("*number")] = 1
+end
+
+--
+-- Read in the rest, printing 1/0 depending on
+-- whether the number is present in the matrix or not.
+--
+while true do
+    target = io . read ("*number")
+    if   target == nil then break end
+    if   matrix [target]
+    then print (1)
+    else print (0)
+    end
+end