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authorRyan Thompson <rjt-pl@users.noreply.github.com>2022-06-16 17:10:46 -0600
committerGitHub <noreply@github.com>2022-06-16 17:10:46 -0600
commitc92803076d8d8f9fee7bb945e0e268399e32cdd3 (patch)
treef59a55e4a378f42fa80a5b6f13238b12088e7d4b /challenge-169/michael-dicicco/java/ch2.java
parent40198d275c123f30a185aea4da69f2c3b9424dab (diff)
parent7c2fa584618da574d42b1713c3c343423991c781 (diff)
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Merge branch 'manwar:master' into master
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1 files changed, 70 insertions, 0 deletions
diff --git a/challenge-169/michael-dicicco/java/ch2.java b/challenge-169/michael-dicicco/java/ch2.java
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+import java.util.ArrayList;
+import java.util.List;
+
+/**
+ *
+ * @author mddicicco
+ */
+public class ch2 {
+ static final double PRECISION = Math.pow(10,12);
+ public static void main(String[] args){
+
+ List<String> achilles_nums = new ArrayList<>();
+
+ for(long i = 72; i < 1801; i++){
+ if(isAchilles(primeFactors(i), i)){
+ achilles_nums.add(Long.toString(i));
+ }
+ }
+ System.out.println(String.join(", ", achilles_nums));
+ }
+ public static Boolean isAchilles(List<Long> factors, Long given){
+ for(Long factor : factors){
+ if(!(given % Math.pow(factor, 2) == 0))
+ return false;
+ }
+
+
+
+ for(long i = 2; i <= 9; i++){
+ double root = Math.round(nthRoot(given, i) * PRECISION)/PRECISION;
+
+ if (Math.floor(root) == root){
+
+ return false;
+ }
+ }
+ return true;
+
+ }
+ public static double nthRoot(double someNumber, double n){
+ return Math.pow(n, ((1.0 / n ) * (Math.log(someNumber) / Math.log(n))));
+ }
+
+ public static List<Long> primeFactors(long n) {
+ List<Long> output = new ArrayList<>();
+
+ // Print the number of 2s that divide n
+ while (n % 2L == 0L) {
+ output.add(2L);
+ n /= 2L;
+ }
+
+ // n must be odd at this point. So we can
+ // skip one element (Note i = i +2)
+ for (long i = 3L; i <= Math.sqrt(n); i += 2L) {
+ // While i divides n, print i and divide n
+ while (n % i == 0) {
+ output.add(i);
+ n /= i;
+ }
+ }
+
+ // This condition is to handle the case when
+ // n is a prime number greater than 2
+ if (n > 2L) {
+ output.add(n);
+ }
+ return output;
+ }
+}