Add Python solutions

5 files changed, 92 insertions, 10 deletions

diff --git a/challenge-178/paulo-custodio/perl/ch-1.pl b/challenge-178/paulo-custodio/perl/ch-1.pl
index 75bbc20fcd..96fbd0cfea 100644
--- a/challenge-178/paulo-custodio/perl/ch-1.pl
+++ b/challenge-178/paulo-custodio/perl/ch-1.pl
@@ -1,4 +1,4 @@
-#!/usr/bin/perl
+#!/usr/bin/env perl
 
 # Challenge 178
 #
@@ -14,7 +14,6 @@
 # $number_quater_imaginary_base = 10300
 
 use Modern::Perl;
-use Test::More;
 
 sub dec_to_base2i {
     my($n) = @_;
@@ -49,6 +48,5 @@ sub base2i_to_dec {
     return $result;
 }
 
-is dec_to_base2i(4), 10300;
-is base2i_to_dec(10300), 4;
-done_testing;
+dec_to_base2i(4) == 10300 or die;
+base2i_to_dec(10300) == 4 or die;
diff --git a/challenge-178/paulo-custodio/perl/ch-2.pl b/challenge-178/paulo-custodio/perl/ch-2.pl
index 6e3e10ce37..53263eb7fd 100644
--- a/challenge-178/paulo-custodio/perl/ch-2.pl
+++ b/challenge-178/paulo-custodio/perl/ch-2.pl
@@ -1,4 +1,4 @@
-#!/usr/bin/perl
+#!/usr/bin/env perl
 
 # Challenge 178
 #
diff --git a/challenge-178/paulo-custodio/python/ch-1.py b/challenge-178/paulo-custodio/python/ch-1.py
new file mode 100644
index 0000000000..a27f6c780d
--- /dev/null
+++ b/challenge-178/paulo-custodio/python/ch-1.py
@@ -0,0 +1,41 @@
+#!/usr/bin/env python3
+
+# Challenge 178
+#
+# Task 1: Quater-imaginary Base
+# Submitted by: Mohammad S Anwar
+#
+# Write a script to convert a given number (base 10) to quater-imaginary base
+# number and vice-versa. For more informations, please checkout wiki page.
+#
+# For example,
+#
+# $number_base_10 = 4
+# $number_quater_imaginary_base = 10300
+
+def dec_to_base2i(n):
+    base = -4
+    result = ""
+    while n != 0:
+        i = n % base
+        n //= base
+        if i < 0:
+            i += abs(base)
+            n += 1
+        result = "0" + str(i) + result  # imaginary is zero
+    result = result.lstrip('0')
+    return result
+
+def base2i_to_dec(n2i):
+    base = -4
+    result = 0
+    digits = list(reversed(n2i))
+    for i in range(len(digits)):
+        if i % 2 == 0:  # real part
+            result += int(digits[i]) * (base ** (i // 2))
+        elif digits[i] != '0':  # imaginary part
+            raise ValueError(f"number {n2i} has imaginary component")
+    return result
+
+assert(dec_to_base2i(4) == '10300')
+assert(base2i_to_dec('10300') == 4)
diff --git a/challenge-178/paulo-custodio/python/ch-2.py b/challenge-178/paulo-custodio/python/ch-2.py
new file mode 100644
index 0000000000..e05c344ec8
--- /dev/null
+++ b/challenge-178/paulo-custodio/python/ch-2.py
@@ -0,0 +1,46 @@
+#!/usr/bin/env python3
+
+# Challenge 178
+#
+# Task 2: Business Date
+# Submitted by: Mohammad S Anwar
+#
+# You are given $timestamp (date with time) and $duration in hours.
+#
+# Write a script to find the time that occurs $duration business hours after
+# $timestamp. For the sake of this task, let us assume the working hours is 9am
+# to 6pm, Monday to Friday. Please ignore timezone too.
+#
+# For example,
+#
+# Suppose the given timestamp is 2022-08-01 10:30 and the duration is 4 hours.
+# Then the next business date would be 2022-08-01 14:30.
+#
+# Similar if the given timestamp is 2022-08-01 17:00 and the duration is 3.5 hours.
+# Then the next business date would be 2022-08-02 11:30.
+
+from datetime import datetime, timedelta
+import sys
+
+def next_business_date(date_text, time_text, hours):
+    date_str = f"{date_text} {time_text}"
+    date = datetime.strptime(date_str, "%Y-%m-%d %H:%M")
+
+    minutes = hours * 60
+    while True:
+        end_day = date.replace(hour=18, minute=0)
+        remain = (end_day - date).total_seconds() / 60
+        if minutes < remain:
+            date += timedelta(minutes=minutes)
+            return date
+        else:
+            minutes -= remain
+            date = end_day + timedelta(hours=(24 - 18) + 9)
+            while date.weekday() >= 5:  # skip weekend
+                date += timedelta(days=1)
+
+if len(sys.argv) != 4:
+    raise ValueError("usage: ch-2.py yyyy-mm-dd HH:MM hours")
+
+result_date = next_business_date(sys.argv[1], sys.argv[2], float(sys.argv[3]))
+print(result_date.strftime("%Y-%m-%d %H:%M"))
diff --git a/challenge-178/paulo-custodio/t/test-1.yaml b/challenge-178/paulo-custodio/t/test-1.yaml
index 5c2d74364b..6e4d99f6fb 100644
--- a/challenge-178/paulo-custodio/t/test-1.yaml
+++ b/challenge-178/paulo-custodio/t/test-1.yaml
@@ -2,7 +2,4 @@
   cleanup:
   args:
   input:
-  output:   |
-            |ok 1
-            |ok 2
-            |1..2
+  output: