- Added solutions by Eric Cheung.

- Added solutions by Laurent Rosenfeld.
- Added solutions by Matthew Neleigh.
- Added solutions by Mark Anderson.
- Added solutions by Luca Ferrari.
- Added solutions by PokGoPun.
- Added solutions by Robbie Hatley.
- Added solutions by Thomas Kohler.
- Added solutions by W. Luis Mochan.
- Added solutions by Simon Proctor.
- Added solutions by Steven Wilson.
- Added solutions by David Ferrone.
- Added solutions by Peter Meszaros.

1 files changed, 37 insertions, 0 deletions

diff --git a/challenge-255/steven-wilson/python/ch-2.py b/challenge-255/steven-wilson/python/ch-2.py
new file mode 100644
index 0000000000..2d5fc3ab9c
--- /dev/null
+++ b/challenge-255/steven-wilson/python/ch-2.py
@@ -0,0 +1,37 @@
+#!/usr/bin/env python3
+
+from collections import Counter
+import string
+
+
+def most_frequent_word(paragraph, banned):
+    '''Given a paragraph and a banned word. Return the most frequent word that
+    is not banned
+    >>> most_frequent_word(
+    ...     "Joe hit a ball, the hit ball flew far after it was hit.", "hit")
+    'ball'
+    >>> most_frequent_word(
+    ...     "Perl and Raku belong to the same family. "
+    ...     "Perl is the most popular language in the weekly challenge.", "the")
+    'Perl'
+    '''
+    if not paragraph or not banned:
+        raise ValueError("Both strings must be non-empty.")
+
+    paragraph_no_punctuation = paragraph.translate(
+        str.maketrans("", "", string.punctuation))
+    paragraph_counter = Counter(paragraph_no_punctuation.split())
+
+    if banned in paragraph_counter:
+        del paragraph_counter[banned]
+
+    if not paragraph_counter:
+        raise ValueError("No words found in the paragraph after removing punctuation and banned word.")
+
+    return paragraph_counter.most_common()[0][0]
+
+
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod()