Merge pull request #10257 from spadacciniweb/PWC-273

PWC 273 - Add ch-1 and ch-2 in Python and Elixir, remake ch-2 in Perl

2 files changed, 107 insertions, 0 deletions

diff --git a/challenge-273/spadacciniweb/python/ch-1.py b/challenge-273/spadacciniweb/python/ch-1.py
new file mode 100644
index 0000000000..bfbc5cbc57
--- /dev/null
+++ b/challenge-273/spadacciniweb/python/ch-1.py
@@ -0,0 +1,61 @@
+# Task 1: Percentage of Character
+# Submitted by: Mohammad Sajid Anwar
+# 
+# You are given a string, $str and a character $char.
+# Write a script to return the percentage, nearest whole, of given character in the given string.
+# 
+# Example 1
+# Input: $str = "perl", $char = "e"
+# Output: 25
+# 
+# Example 2
+# Input: $str = "java", $char = "a"
+# Output: 50
+# 
+# Example 3
+# Input: $str = "python", $char = "m"
+# Output: 0
+# 
+# Example 4
+# Input: $str = "ada", $char = "a"
+# Output: 67
+# 
+# Example 5
+# Input: $str = "ballerina", $char = "l"
+# Output: 22
+# 
+# Example 6
+# Input: $str = "analitik", $char = "k"
+# Output: 13
+
+def percentage(str, char):
+    print("%s -> %d" % 
+             ( str, 
+               round( str.count(char)*100/len(str) )
+             )
+    )
+
+if __name__ == "__main__":
+    str = "perl"
+    char = "e"
+    percentage(str, char)
+
+    str = "java"
+    char = "a"
+    percentage(str, char)
+
+    str = "python"
+    char = "m"
+    percentage(str, char)
+
+    str = "ada"
+    char = "a"
+    percentage(str, char)
+
+    str = "ballerina"
+    char = "l"
+    percentage(str, char)
+
+    str = "analitik"
+    char = "k"
+    percentage(str, char)
diff --git a/challenge-273/spadacciniweb/python/ch-2.py b/challenge-273/spadacciniweb/python/ch-2.py
new file mode 100644
index 0000000000..dce0bca454
--- /dev/null
+++ b/challenge-273/spadacciniweb/python/ch-2.py
@@ -0,0 +1,46 @@
+#!/usr/bin/env perl
+
+# Task 2: B After A
+# Submitted by: Mohammad Sajid Anwar
+# 
+# You are given a string, $str.
+# Write a script to return true if there is at least one b, and no a appears after the first b.
+# 
+# Example 1
+# Input: $str = "aabb"
+# Output: true
+# 
+# Example 2
+# Input: $str = "abab"
+# Output: false
+# 
+# Example 3
+# Input: $str = "aaa"
+# Output: false
+# 
+# Example 4
+# Input: $str = "bbb"
+# Output: true
+
+def out(str):
+    offset = str.find('b')
+    if offset >= 0 and str.find('a', offset) == -1:
+        res = "true"
+    else:
+        res = "false"
+    print("%s -> %s" % 
+             ( str, res )
+    )
+
+if __name__ == "__main__":
+    str = "aabb"
+    out(str)
+
+    str = "abab"
+    out(str)
+
+    str = "aaa"
+    out(str)
+
+    str = "bbb"
+    out(str)