pwc281 solution in python

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diff --git a/challenge-281/pokgopun/python/ch-1.py b/challenge-281/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-281/
+"""
+
+Task 1: Check Color
+
+Submitted by: [47]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given coordinates, a string that represents the coordinates of
+   a square of the chessboard as shown below:
+
+   Week_281_Task_1
+
+   Write a script to return true if the square is light, and false if the
+   square is dark.
+
+Example 1
+
+Input: $coordinates = "d3"
+Output: true
+
+Example 2
+
+Input: $coordinates = "g5"
+Output: false
+
+Example 3
+
+Input: $coordinates = "e6"
+Output: true
+
+Task 2: Knight’s Move
+"""
+### solution by pokgopun@gmail.com
+
+def checkColor(string: str):
+    return sum(
+            ord(c) for c in string
+            ) % 2 == 1
+
+import unittest
+
+class TestCheckColor(unittest.TestCase):
+    def test(self):
+        for inpt, otpt in {
+                "d3": True,
+                "g5": False,
+                "e6": True,
+                }.items():
+            self.assertEqual(checkColor(inpt),otpt)
+
+unittest.main()
diff --git a/challenge-281/pokgopun/python/ch-2.py b/challenge-281/pokgopun/python/ch-2.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-281/
+"""
+
+Task 2: Knight’s Move
+
+Submitted by: [48]Peter Campbell Smith
+     __________________________________________________________________
+
+   A Knight in chess can move from its current position to any square two
+   rows or columns plus one column or row away. So in the diagram below,
+   if it starts a S, it can move to any of the squares marked E.
+
+   Write a script which takes a starting position and an ending position
+   and calculates the least number of moves required.
+
+   Week_281_Task_2
+
+Example 1
+
+Input: $start = 'g2', $end = 'a8'
+Ouput: 4
+
+g2 -> e3 -> d5 -> c7 -> a8
+
+Example 2
+
+Input: $start = 'g2', $end = 'h2'
+Ouput: 3
+
+g2 -> e3 -> f1 -> h2
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 11th August
+   2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+### https://afteracademy.com/blog/knight-on-chessboard/#:~:text=Solution,the%20shape%20of%20an%20L).
+
+def pos2xy(string: str):
+    return ord(string[0])-97, ord(string[1])-49
+
+def xy2pos(x, y):
+    return chr(97+x)+chr(49+y)
+
+def isOnBoard(x, y):
+    return x >=0 and x < 8 and y >= 0 and y < 8
+
+def knightMove(start, end):
+    XYd = ( (-2,-1), (-1,-2), ( 1,-2), ( 2,-1), (-2, 1), (-1, 2), ( 1, 2), ( 2, 1) )
+    XYa = tuple([None for y in range(8)] for x in range(8))
+    x0, y0 = pos2xy(start)
+    x1, y1 = pos2xy(end)
+    #XYa[x0][y0] = 0
+    XYa[x0][y0] = ""
+    XYq = [(x0, y0)]
+    while len(XYq) > 0:
+        x, y = XYq.pop(0)
+        if (x,y) == (x1,y1):
+            #return XYa[x][y]
+            print(XYa[x][y]+end,"=>",int(len(XYa[x][y])/2))
+            return int(len(XYa[x][y])/2)
+        for dx, dy in XYd:
+            xn, yn = x + dx, y + dy
+            if isOnBoard(xn, yn) and XYa[xn][yn] is None:
+                #XYa[xn][yn] = XYa[x][y] + 1
+                XYa[xn][yn] = XYa[x][y] + xy2pos(x,y)
+                XYq.append((xn,yn))
+    return -1
+
+import unittest
+
+class TestKnightMove(unittest.TestCase):
+    def test(self):
+        for (start,end), count in {
+                ('g2', 'a8'): 4,
+                ('g2', 'h2'): 3,
+                }.items():
+            self.assertEqual(knightMove(start, end), count)
+
+unittest.main()