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authorMohammad Sajid Anwar <Mohammad.Anwar@yahoo.com>2024-09-18 19:59:32 +0100
committerGitHub <noreply@github.com>2024-09-18 19:59:32 +0100
commit85073f31dae3decce780d1fd66cdcb79c82c7f65 (patch)
tree318d3bc02836f4cde215f7f15e9ec875c74a1490 /challenge-286/paulo-custodio/python/ch-2.py
parentbfe139d559d498bcf1ae48cc08520bfc99ee9b85 (diff)
parent51c035e04c5ae5f9f02555206f57eb675a737617 (diff)
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Merge pull request #10860 from pauloscustodio/master
Add Python solutions
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+#!/usr/bin/env python3
+
+# Challenge 286
+#
+# Task 2: Order Game
+# Submitted by: Mohammad Sajid Anwar
+#
+# You are given an array of integers, @ints, whose length is a power of 2.
+#
+# Write a script to play the order game (min and max) and return the last element.
+# Example 1
+#
+# Input: @ints = (2, 1, 4, 5, 6, 3, 0, 2)
+# Output: 1
+#
+# Operation 1:
+#
+# min(2, 1) = 1
+# max(4, 5) = 5
+# min(6, 3) = 3
+# max(0, 2) = 2
+#
+# Operation 2:
+#
+# min(1, 5) = 1
+# max(3, 2) = 3
+#
+# Operation 3:
+#
+# min(1, 3) = 1
+#
+# Example 2
+#
+# Input: @ints = (0, 5, 3, 2)
+# Output: 0
+#
+# Operation 1:
+#
+# min(0, 5) = 0
+# max(3, 2) = 3
+#
+# Operation 2:
+#
+# min(0, 3) = 0
+#
+# Example 3
+#
+# Input: @ints = (9, 2, 1, 4, 5, 6, 0, 7, 3, 1, 3, 5, 7, 9, 0, 8)
+# Output: 2
+#
+# Operation 1:
+#
+# min(9, 2) = 2
+# max(1, 4) = 4
+# min(5, 6) = 5
+# max(0, 7) = 7
+# min(3, 1) = 1
+# max(3, 5) = 5
+# min(7, 9) = 7
+# max(0, 8) = 8
+#
+# Operation 2:
+#
+# min(2, 4) = 2
+# max(5, 7) = 7
+# min(1, 5) = 1
+# max(7, 8) = 8
+#
+# Operation 3:
+#
+# min(2, 7) = 2
+# max(1, 8) = 8
+#
+# Operation 4:
+#
+# min(2, 8) = 2
+
+import sys
+
+def reduce(nums):
+ out = []
+ while len(nums) > 0:
+ if len(nums) >= 2:
+ out.append(min(nums[0], nums[1]))
+ if len(nums) >= 4:
+ out.append(max(nums[2], nums[3]))
+ nums = nums[4:]
+ return out
+
+nums = list(map(int, sys.argv[1:]))
+while len(nums) > 1:
+ nums = reduce(nums)
+
+print(nums[0])