- Added solutions by Eric Cheung.

- Added solutions by Ulrich Rieke.
- Added solutions by David Ferrone.
- Added solutions by E. Choroba.
- Added solutions by Mark Anderson.
- Added solutions by Jaldhar H. Vyas.
- Added solutions by Ali Moradi.
- Added solutions by Feng Chang.
- Added solutions by Vinod Kumar K.
- Added solutions by Peter Campbell Smith.
- Added solutions by Ali Moradi.
- Added solutions by Feng Chang.
- Added solutions by Conor Hoekstra.
- Added solutions by Bob Lied.
- Added solutions by Athanasius.
- Added solutions by W. Luis Mochan.
- Added solutions by Andrew Shitov.
- Added solutions by PokGoPun.
- Added solutions by Roger Bell_West.

1 files changed, 44 insertions, 0 deletions

diff --git a/challenge-320/ulrich-rieke/cpp/ch-2.cpp b/challenge-320/ulrich-rieke/cpp/ch-2.cpp
new file mode 100755
index 0000000000..9950e4e891
--- /dev/null
+++ b/challenge-320/ulrich-rieke/cpp/ch-2.cpp
@@ -0,0 +1,44 @@
+#include <iostream>

+#include <sstream>

+#include <numeric>

+#include <string>

+#include <vector>

+#include <cstdlib>

+

+std::vector<std::string> split( const std::string & text , char delimiter ) {

+   std::vector<std::string> tokens ;

+   std::istringstream istr { text } ;

+   std::string word ;

+   while ( std::getline( istr , word , delimiter ) ) 

+      tokens.push_back( word ) ;

+   return tokens ;

+}

+

+int digitsum( int number ) {

+   int sum = 0 ;

+   while ( number != 0 ) {

+      sum += number % 10 ;

+      number /= 10 ;

+   }

+   return sum ;

+}

+

+int main( ) {

+   std::cout << "Enter some positive integers separated by blanks!\n" ;

+   std::string line ;

+   std::getline( std::cin , line ) ;

+   auto tokens { split( line , ' ' ) } ;

+   std::vector<int> numbers ;

+   for ( auto s : tokens ) 

+      numbers.push_back( std::stoi( s ) ) ;

+   int numbersum = std::accumulate( numbers.begin( ) , numbers.end( ) , 0 ) ;

+   std::vector<int> digitsums ;

+   for ( int n : numbers ) {

+      digitsums.push_back( digitsum( n ) ) ;

+   }

+   int all_digit_sum = std::accumulate( digitsums.begin( ) , digitsums.end( ) , 

+	 0 ) ;

+   std::cout << std::abs( all_digit_sum - numbersum ) << '\n' ;

+   return 0 ;

+}

+