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+#!/usr/bin/perl
+
+# Weekly Challenge 141 Task 1
+#
+# Write a script to find lowest 10 positive integers having exactly 8 divisors.
+
+use strict;
+
+my @numbers;
+my @final;
+my $i=8;
+my $j=1;
+
+# Loop through until 8 numbers are found.
+while ($#final < 7) {
+  # Loop through all possible divisors. Must
+  # go through all of them up to the number
+  # being tested to ensure there are only 8.
+  for ($j=1; $j<=$i; $j++) {
+    if (($i % $j) eq 0) {
+      push @numbers, $i;
+    }
+  }
+  push @final, $i if $#numbers == 7;
+  $i++;
+  undef(@numbers);
+}
+
+print "The first 8 integers to have exactly 8 divisors:\n@final\n";