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diff --git a/challenge-235/pokgopun/python/ch-1.py b/challenge-235/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-235/
+"""
+
+Task 1: Remove One
+
+Submitted by: [44]Mohammad S Anwar
+     __________________________________________________________________
+
+   You are given an array of integers.
+
+   Write a script to find out if removing ONLY one integer makes it
+   strictly increasing order.
+
+Example 1
+
+Input: @ints = (0, 2, 9, 4, 6)
+Output: true
+
+Removing ONLY 9 in the given array makes it strictly increasing order.
+
+Example 2
+
+Input: @ints = (5, 1, 3, 2)
+Output: false
+
+Example 3
+
+Input: @ints = (2, 2, 3)
+Output: true
+
+Task 2: Duplicate Zeros
+"""
+### solution by pokgopun@gmail.com
+
+def isRmoSorted(lst):
+    l = len(lst)
+    for i in range(l):
+        v = None
+        isSorted = True
+        for j in range(l):
+            if j == i: continue
+            if v != None:
+                #print(v,j)
+                if lst[v] > lst[j]:
+                    isSorted = False
+                    break
+            v = j
+        if isSorted == True: return True
+    return False
+
+for inpt,otpt in {
+        (0, 2, 9, 4, 6): True,
+        (5, 1, 3, 2): False,
+        (2, 2, 3): True,
+        }.items():
+    print(isRmoSorted(inpt)==otpt)
diff --git a/challenge-235/pokgopun/python/ch-2.py b/challenge-235/pokgopun/python/ch-2.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-235/
+"""
+
+Task 2: Duplicate Zeros
+
+Submitted by: [45]Mohammad S Anwar
+     __________________________________________________________________
+
+   You are given an array of integers.
+
+   Write a script to duplicate each occurrence of ZERO in the given array
+   and shift the remaining to the right but make sure the size of array
+   remain the same.
+
+Example 1
+
+Input: @ints = (1, 0, 2, 3, 0, 4, 5, 0)
+Ouput: (1, 0, 0, 2, 3, 0, 0, 4)
+
+Example 2
+
+Input: @ints = (1, 2, 3)
+Ouput: (1, 2, 3)
+
+Example 3
+
+Input: @ints = (0, 3, 0, 4, 5)
+Ouput: (0, 0, 3, 0, 0)
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 24th September
+   2023.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def dupZero(tup):
+    lst = list(tup)
+    l = len(lst)
+    i = 0
+    while i < l:
+        if lst[i]==0:
+            lst.insert(i,0)
+            i += 1
+        i += 1
+    return tuple(lst[:l])
+
+for inpt,otpt in {
+        (1, 0, 2, 3, 0, 4, 5, 0): (1, 0, 0, 2, 3, 0, 0, 4), 
+        (1, 2, 3): (1, 2, 3),
+        (0, 3, 0, 4, 5): (0, 0, 3, 0, 0),
+        }.items():
+    print(dupZero(inpt)==otpt)
+
+