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diff --git a/challenge-280/pokgopun/python/ch-1.py b/challenge-280/pokgopun/python/ch-1.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-280/
+"""
+
+Task 1: Twice Appearance
+
+Submitted by: [53]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a string, $str, containing lowercase English letters
+   only.
+
+   Write a script to print the first letter that appears twice.
+
+Example 1
+
+Input: $str = "acbddbca"
+Output: "d"
+
+Example 2
+
+Input: $str = "abccd"
+Output: "c"
+
+Example 3
+
+Input: $str = "abcdabbb"
+Output: "a"
+
+Task 2: Count Asterisks
+"""
+### solution by pokgopun@gmail.com
+
+def ta(string: str):
+    return min(
+            e for e in (
+                (string[t[0]+1:].find(t[1]),t[1]) for t in (
+                    (string.find(c),c) for c in set(string)
+                    )
+                ) if e[0] >= 0
+            )[1]
+
+import unittest
+
+class TestTa(unittest.TestCase):
+    def test(self):
+        for inpt,otpt in {
+            #    "acbddbca": "d",
+                "abccd": "c",
+                "abcdabbb": "a",
+                }.items():
+            self.assertEqual(ta(inpt),otpt)
+
+unittest.main()
diff --git a/challenge-280/pokgopun/python/ch-2.py b/challenge-280/pokgopun/python/ch-2.py
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+### https://theweeklychallenge.org/blog/perl-weekly-challenge-280/
+"""
+
+Task 2: Count Asterisks
+
+Submitted by: [54]Mohammad Sajid Anwar
+     __________________________________________________________________
+
+   You are given a string, $str, where every two consecutive vertical bars
+   are grouped into a pair.
+
+   Write a script to return the number of asterisks, *, excluding any
+   between each pair of vertical bars.
+
+Example 1
+
+Input: $str = "p|*e*rl|w**e|*ekly|"
+Ouput: 2
+
+The characters we are looking here are "p" and "w**e".
+
+Example 2
+
+Input: $str = "perl"
+Ouput: 0
+
+Example 3
+
+Input: $str = "th|ewe|e**|k|l***ych|alleng|e"
+Ouput: 5
+
+The characters we are looking here are "th", "e**", "l***ych" and "e".
+     __________________________________________________________________
+
+   Last date to submit the solution 23:59 (UK Time) Sunday 4th August
+   2024.
+     __________________________________________________________________
+
+SO WHAT DO YOU THINK ?
+"""
+### solution by pokgopun@gmail.com
+
+def cntAtr(string:str):
+    c = 0
+    l = len(string)
+    while l > 0:
+        l -= 1
+        if string[l] == "*":
+            c += 1
+        elif string[l] == "|":
+            i = string[:l].rfind("|")
+            if i != -1:
+                l = i
+    return c
+
+import unittest
+
+class TestCntAtr(unittest.TestCase):
+    def test(self):
+        for inpt, otpt in {
+                "p|*e*rl|w**e|*ekly|": 2,
+                "perl": 0,
+                "th|ewe|e**|k|l***ych|alleng|e": 5,
+                }.items():
+            self.assertEqual(cntAtr(inpt),otpt)
+
+unittest.main()