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| -rw-r--r-- | challenge-260/pokgopun/python/ch-1.py | 56 | ||||
| -rw-r--r-- | challenge-260/pokgopun/python/ch-2.py | 68 |
2 files changed, 124 insertions, 0 deletions
diff --git a/challenge-260/pokgopun/python/ch-1.py b/challenge-260/pokgopun/python/ch-1.py new file mode 100644 index 0000000000..734382ae7c --- /dev/null +++ b/challenge-260/pokgopun/python/ch-1.py @@ -0,0 +1,56 @@ +### https://theweeklychallenge.org/blog/perl-weekly-challenge-260/ +""" + +Task 1: Unique Occurrences + +Submitted by: [42]Mohammad Sajid Anwar + __________________________________________________________________ + + You are given an array of integers, @ints. + + Write a script to return 1 if the number of occurrences of each value + in the given array is unique or 0 otherwise. + +Example 1 + +Input: @ints = (1,2,2,1,1,3) +Output: 1 + +The number 1 occurred 3 times. +The number 2 occurred 2 times. +The number 3 occurred 1 time. + +All occurrences are unique, therefore the output is 1. + +Example 2 + +Input: @ints = (1,2,3) +Output: 0 + +Example 3 + +Input: @ints = (-2,0,1,-2,1,1,0,1,-2,9) +Output: 1 + +Task 2: Dictionary Rank +""" +### solution by pokgopun@gmail.com + +def UO(tup: tuple): + s = set(tup) + return len(s)==len(set(tup.count(e) for e in s)) + +import unittest + +class TestUO(unittest.TestCase): + def test(self): + for inpt, otpt in { + (1,2,2,1,1,3): 1, + (1,2,3): 0, + (-2,0,1,-2,1,1,0,1,-2,9): 1, + }.items(): + self.assertEqual(UO(inpt),otpt) + +unittest.main() + + diff --git a/challenge-260/pokgopun/python/ch-2.py b/challenge-260/pokgopun/python/ch-2.py new file mode 100644 index 0000000000..6925831197 --- /dev/null +++ b/challenge-260/pokgopun/python/ch-2.py @@ -0,0 +1,68 @@ +### https://theweeklychallenge.org/blog/perl-weekly-challenge-260/ +""" + +Task 2: Dictionary Rank + +Submitted by: [43]Mark Anderson + __________________________________________________________________ + + You are given a word, $word. + + Write a script to compute the dictionary rank of the given word. + +Example 1 + +Input: $word = 'CAT' +Output: 3 + +All possible combinations of the letters: +CAT, CTA, ATC, TCA, ACT, TAC + +Arrange them in alphabetical order: +ACT, ATC, CAT, CTA, TAC, TCA + +CAT is the 3rd in the list. +Therefore the dictionary rank of CAT is 3. + +Example 2 + +Input: $word = 'GOOGLE' +Output: 88 + +Example 3 + +Input: $word = 'SECRET' +Output: 255 + __________________________________________________________________ + + Last date to submit the solution 23:59 (UK Time) Sunday 17th March + 2024. + __________________________________________________________________ + +SO WHAT DO YOU THINK ? +""" +### solution by pokgopun@gmail.com + +from itertools import permutations + +def DC(word: str): + return tuple( + sorted( + set( + permutations(word,len(word)) + ) + ) + ).index(tuple(word)) + 1 + +import unittest + +class TestDC(unittest.TestCase): + def test(self): + for inpt, otpt in { + 'CAT': 3, + 'GOOGLE': 88, + 'SECRET': 255, + }.items(): + self.assertEqual(DC(inpt),otpt) + +unittest.main() |
