diff options
| -rwxr-xr-x | challenge-249/jo-37/perl/ch-1.pl | 62 | ||||
| -rwxr-xr-x | challenge-249/jo-37/perl/ch-2.pl | 83 |
2 files changed, 145 insertions, 0 deletions
diff --git a/challenge-249/jo-37/perl/ch-1.pl b/challenge-249/jo-37/perl/ch-1.pl new file mode 100755 index 0000000000..df8c652043 --- /dev/null +++ b/challenge-249/jo-37/perl/ch-1.pl @@ -0,0 +1,62 @@ +#!/usr/bin/perl -s + +use v5.24; +use Test2::V0; + +our ($tests, $examples); + +run_tests() if $tests || $examples; # does not return + +die <<EOS unless @ARGV; +usage: $0 [-examples] [-tests] [N...] + +-examples + run the examples from the challenge + +-tests + run some tests + +N... + list of numbers + +EOS + + +### Input and Output + +say join ", ", map "(@$_)", equal_pairs(@ARGV); + + +### Implementation + +# Count the frequencies of all given numbers, check if these are all +# even and build equal pairs. + +sub equal_pairs { + my %freq; + $freq{$_}++ for @_; + return () if grep $_ % 2, values %freq; + + map +([$_, $_]) x ($freq{$_} / 2), keys %freq; +} + + +### Examples and tests + +sub run_tests { + SKIP: { + skip "examples" unless $examples; + + is [equal_pairs(3, 2, 3, 2, 2, 2)], + bag {item [2, 2]; item [2, 2]; item [3, 3]; end;}, 'example 1'; + + is [equal_pairs(1, 2, 3, 4)], [] , 'example 2'; + } + + SKIP: { + skip "tests" unless $tests; + } + + done_testing; + exit; +} diff --git a/challenge-249/jo-37/perl/ch-2.pl b/challenge-249/jo-37/perl/ch-2.pl new file mode 100755 index 0000000000..4d440602ff --- /dev/null +++ b/challenge-249/jo-37/perl/ch-2.pl @@ -0,0 +1,83 @@ +#!/usr/bin/perl -s + +use v5.24; +use Test2::V0; + +our ($tests, $examples); + +run_tests() if $tests || $examples; # does not return + +die <<EOS unless @ARGV; +usage: $0 [-examples] [-tests] [DI] + +-examples + run the examples from the challenge + +-tests + run some tests + +DI + a string consisting of 'D's and 'I's + +EOS + + +### Input and Output + +say "(@{[arrange_di(shift)]})"; + + +### Implementation + +# First we transform the DI-string into an array of zeroes and ones +# where a zero represents a decrement and a one an increment. Lets +# assume the DI-string and the corresponding array have a length of L, +# there are ND 'D's / zeroes and NI 'I's / ones. +# Then we create two sequences: +# - SD as the numbers 0 .. ND - 1 in descending order +# - SI the numbers ND .. L - 1 in ascending order. +# It can be seen that: +# - Every element of SI is larger than any element of SD. +# - Every element of SD is smaller than any element of SI. +# - Every but the last element of SI is smaller than its successor. +# - Every but the last element of DI is larger than its successor. +# Now we can construct a permutation with the required incremental / +# decremental behaviour by successively picking the first element from +# the corresponding sequence - except for the very first. +# The first element of our permutation may be chosen as follows: +# - If the first step is a decrement, we just take L as the first +# element. +# - Otherwise, we pick the first element from the incremental sequence SI +# and append L to SI + +sub arrange_di { + my @di = map tr/DI/01/r, split //, shift; + my @count = (0, 0); + $count[$_]++ for @di; + my @pool = ([reverse 0 .. $count[0] - 1], [$count[0] .. $#di]); + + ($di[0] ? + do {push $pool[1]->@*, scalar @di; shift $pool[1]->@*} : + scalar @di, + map shift $pool[$_]->@*, @di); +} + + +### Examples and tests + +sub run_tests { + SKIP: { + skip "examples" unless $examples; + + is [arrange_di('IDID')], [2, 3, 1, 4, 0], 'example 1'; + is [arrange_di('III')], [0, 1, 2, 3], 'example 2'; + is [arrange_di('DDI')], [3, 1, 0, 2], 'example 3'; + } + + SKIP: { + skip "tests" unless $tests; + } + + done_testing; + exit; +} |
