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+#!/usr/bin/env python3
+
+# Challenge 061
+#
+# TASK #2 > IPv4 Partition
+# Reviewed by: Ryan Thompson
+# You are given a string containing only digits (0..9). The string should have
+# between 4 and 12 digits.
+#
+# Write a script to print every possible valid IPv4 address that can be made by
+# partitioning the input string.
+#
+# For the purpose of this challenge, a valid IPv4 address consists of four
+# "octets" i.e. A, B, C and D, separated by dots (.).
+#
+# Each octet must be between 0 and 255, and must not have any leading zeroes.
+# (e.g., 0 is OK, but 01 is not.)
+#
+# Example
+# Input: 25525511135,
+#
+# Output:
+#
+# 255.255.11.135
+# 255.255.111.35
+
+import re
+import sys
+
+def partition1(prefix, digits):
+    if re.search(r'^(\d+\.){4}$', prefix):
+        if digits == "":
+            prefix = prefix[:-1]
+            print(prefix)
+    else:
+        for l in range(1, 4):
+            if l <= len(digits):
+                part = digits[:l]
+                if int(part) <= 255:
+                    partition1(prefix+part+".", digits[l:])
+
+def partition(digits):
+    partition1("", digits)
+
+digits = sys.argv[1]
+partition(digits)