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-rw-r--r--challenge-078/abigail/Part2/input12
-rw-r--r--challenge-078/abigail/Part2/input22
-rw-r--r--challenge-078/abigail/Part2/output1.exp2
-rw-r--r--challenge-078/abigail/Part2/output2.exp3
-rwxr-xr-xchallenge-078/abigail/Part2/solution.pl42
5 files changed, 51 insertions, 0 deletions
diff --git a/challenge-078/abigail/Part2/input1 b/challenge-078/abigail/Part2/input1
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+10 20 30 40 50
+3 4
diff --git a/challenge-078/abigail/Part2/input2 b/challenge-078/abigail/Part2/input2
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+7 4 2 6 3
+1 3 4
diff --git a/challenge-078/abigail/Part2/output1.exp b/challenge-078/abigail/Part2/output1.exp
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+40 50 10 20 30
+50 10 20 30 40
diff --git a/challenge-078/abigail/Part2/output2.exp b/challenge-078/abigail/Part2/output2.exp
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+4 2 6 3 7
+6 3 7 4 2
+3 7 4 2 6
diff --git a/challenge-078/abigail/Part2/solution.pl b/challenge-078/abigail/Part2/solution.pl
new file mode 100755
index 0000000000..80e8f4907d
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+++ b/challenge-078/abigail/Part2/solution.pl
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+#!/opt/perl/bin/perl
+
+#
+# Exercise:
+#
+# You are given array @A containing positive numbers and @B containing
+# one or more indices from the array @A.
+# Write a script to left rotate @A so that the number at the first index
+# of @B becomes the first element in the array. Similary, left rotate @A
+# again so that the number at the second index of @B becomes the first
+# element in the array.
+#
+
+#
+# We will be reading the arrays from STDIN -- @A is one the first
+# line, @B is on the second line.
+#
+
+use 5.032;
+
+use strict;
+use warnings;
+no warnings 'syntax';
+
+use experimental 'signatures';
+
+#
+# Read @A and @B
+#
+chomp (my @A = split / / => scalar <>);
+chomp (my @B = split / / => scalar <>);
+
+#
+# Print the rotations.
+#
+foreach my $index (@B) {
+ local $, = " ";
+ say @A [$index .. @A - 1, 0 .. $index - 1];
+}
+
+
+__END__