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diff --git a/challenge-102/paulo-custodio/python/ch-1.py b/challenge-102/paulo-custodio/python/ch-1.py
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+#!/usr/bin/env python
+
+# Challenge 102
+#
+# TASK #1 > Rare Numbers
+# Submitted by: Mohammad S Anwar
+#
+# You are given a positive integer $N.
+#
+# Write a script to generate all Rare numbers of size $N if exists. Please
+# checkout the page for more information about it.
+# Examples
+#
+# (a) 2 digits: 65
+# (b) 6 digits: 621770
+# (c) 9 digits: 281089082
+
+import sys
+import math
+
+def perfect_square(n):
+    sq = math.sqrt(float(n))
+    if math.floor(sq) == sq:
+        return True
+    else:
+        return False
+
+def print_rare(n):
+    for r in range(10**(n-1), 10**n):
+        r1 = int(str(r)[::-1])
+        if perfect_square(r+r1):
+            if r>=r1:
+                if perfect_square(r-r1):
+                    print(r)
+
+print_rare(int(sys.argv[1]))
diff --git a/challenge-102/paulo-custodio/python/ch-2.py b/challenge-102/paulo-custodio/python/ch-2.py
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+#!/usr/bin/env python
+
+# Challenge 102
+#
+# TASK #2 > Hash-counting String
+# Submitted by: Stuart Little
+#
+# You are given a positive integer $N.
+#
+# Write a script to produce Hash-counting string of that length.
+#
+# The definition of a hash-counting string is as follows:
+# - the string consists only of digits 0-9 and hashes, '#'
+# - there are no two consecutive hashes: '##' does not appear in your string
+# - the last character is a hash
+# - the number immediately preceding each hash (if it exists) is the position
+# of that hash in the string, with the position being counted up from 1
+#
+# It can be shown that for every positive integer N there is exactly one such
+# length-N string.
+# Examples:
+#
+# (a) "#" is the counting string of length 1
+# (b) "2#" is the counting string of length 2
+# (c) "#3#" is the string of length 3
+# (d) "#3#5#7#10#" is the string of length 10
+# (e) "2#4#6#8#11#14#" is the string of length 14
+
+import sys
+
+def hash_counting(n):
+    out = ''
+    i = n
+    while i>0:
+        p = i
+        out = '#'+out
+        i -= 1
+        while i>0 and p!=0:
+            out = str(p % 10)+out
+            i -= 1
+            p = int(p/10)
+    return out
+
+print(hash_counting(int(sys.argv[1])))