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+/*
+Challenge 120
+
+TASK #2 › Clock Angle
+Submitted by: Mohammad S Anwar
+You are given time $T in the format hh:mm.
+
+Write a script to find the smaller angle formed by the hands of an analog
+clock at a given time.
+
+HINT: A analog clock is divided up into 12 sectors. One sector represents 30
+degree (360/12 = 30).
+
+Example
+Input: $T = '03:10'
+Output: 35 degree
+
+The distance between the 2 and the 3 on the clock is 30 degree.
+For the 10 minutes i.e. 1/6 of an hour that have passed.
+The hour hand has also moved 1/6 of the distance between the 3 and the 4,
+which adds 5 degree (1/6 of 30).
+The total measure of the angle is 35 degree.
+
+Input: $T = '04:00'
+Output: 120 degree
+*/
+
+#include <iostream>
+#include <sstream>
+#include <string>
+using namespace std;
+
+bool parse_time(const string& hhmm, int* hh, int* mm) {
+    *hh = *mm = 0;
+    istringstream iss(hhmm);
+    char c;
+    if (!(iss >> *hh)) return false;
+    if (!(iss >> c) || c != ':') return false;
+    if (!(iss >> *mm)) return false;
+    return true;
+}
+
+int clock_angle(int hh, int mm) {
+    int mm_angle = mm*360/60;
+    int hh_angle = (hh % 12)*360/12 + mm_angle/12;
+    int angle = abs(hh_angle - mm_angle);
+    if (angle > 180) { angle = 360 - angle; }
+    return angle;
+}
+
+int main(int argc, char* argv[]) {
+    if (argc != 2) return EXIT_FAILURE;
+    int hh, mm;
+    if (!parse_time(argv[1], &hh, &mm)) return EXIT_FAILURE;
+    int angle = clock_angle(hh, mm);
+    cout << angle << endl;
+}