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+#!/usr/bin/env python
+
+# Challenge 120
+#
+# TASK #2 - Clock Angle
+# Submitted by: Mohammad S Anwar
+# You are given time $T in the format hh:mm.
+#
+# Write a script to find the smaller angle formed by the hands of an analog
+# clock at a given time.
+#
+# HINT: A analog clock is divided up into 12 sectors. One sector represents 30
+# degree (360/12 = 30).
+#
+# Example
+# Input: $T = '03:10'
+# Output: 35 degree
+#
+# The distance between the 2 and the 3 on the clock is 30 degree.
+# For the 10 minutes i.e. 1/6 of an hour that have passed.
+# The hour hand has also moved 1/6 of the distance between the 3 and the 4,
+# which adds 5 degree (1/6 of 30).
+# The total measure of the angle is 35 degree.
+#
+# Input: $T = '04:00'
+# Output: 120 degree
+
+import sys
+
+def clock_angles(hh, mm):
+    mm_angle = mm * 360 // 60
+    hh_angle = (hh % 12) * 360 // 12 + mm_angle // 12
+    return hh_angle, mm_angle
+
+hh, mm = [int(x) for x in sys.argv[1].split(':')]
+hh_angle, mm_angle = clock_angles(hh, mm)
+angle = abs(hh_angle - mm_angle)
+if angle > 180:
+    angle = 360 - angle
+print(angle)