2 files changed, 149 insertions, 0 deletions
diff --git a/challenge-145/roger-bell-west/python/ch-1.py b/challenge-145/roger-bell-west/python/ch-1.py
new file mode 100755
index 0000000000..83464b868f
--- /dev/null
+++ b/challenge-145/roger-bell-west/python/ch-1.py
@@ -0,0 +1,16 @@
+#! /usr/bin/python3
+
+import unittest
+
+def dotproduct(a,b):
+  p=0
+  for i,v in enumerate(a):
+    p+=v*b[i]
+  return p
+
+class TestDotproduct(unittest.TestCase):
+
+        def test_ex1(self):
+          self.assertEqual(dotproduct([1,2,3],[4,5,6]),32,'example 1')
+
+unittest.main()
diff --git a/challenge-145/roger-bell-west/python/ch-2.py b/challenge-145/roger-bell-west/python/ch-2.py
new file mode 100755
index 0000000000..0a3aabbb70
--- /dev/null
+++ b/challenge-145/roger-bell-west/python/ch-2.py
@@ -0,0 +1,133 @@
+#! /usr/bin/python3
+
+# Very lightly modified from https://rosettacode.org/wiki/Eertree#Python
+# by "TimSC"
+
+import unittest
+
+def eertree(st):
+    eertree=Eertree()
+    for ch in st:
+        eertree.add(ch)
+    result = []
+    eertree.get_sub_palindromes(eertree.rto, [eertree.rto], [], result)
+    eertree.get_sub_palindromes(eertree.rte, [eertree.rte], [], result)
+    q=set(result)
+    res=[]
+    for i in range(len(st)):
+        for j in range(i,len(st)):
+            k=st[i:j+1]
+            if k in q:
+                res.append(k)
+                q.discard(k)
+    return res
+
+class Eernode(object):
+    def __init__(self):
+        self.edges = {} # edges (or forward links)
+        self.link = None # suffix link (backward links)
+        self.len = 0 # the length of the node
+        
+class Eertree(object):
+    def __init__(self):
+        self.nodes = []
+        # two initial root nodes
+        self.rto = Eernode() #odd length root node, or node -1
+        self.rte = Eernode() #even length root node, or node 0
+        
+        # Initialize empty tree
+        self.rto.link = self.rte.link = self.rto;
+        self.rto.len = -1
+        self.rte.len = 0
+        self.S = [0] # accumulated input string, T=S[1..i]
+        self.maxSufT = self.rte # maximum suffix of tree T
+        
+    def get_max_suffix_pal(self, startNode, a):
+        # We traverse the suffix-palindromes of T in the order of decreasing length.
+        # For each palindrome we read its length k and compare T[i-k] against a
+        # until we get an equality or arrive at the -1 node.
+        u = startNode
+        i = len(self.S)
+        k = u.len
+        while id(u) != id(self.rto) and self.S[i - k - 1] != a:
+            assert id(u) != id(u.link) #Prevent infinte loop
+            u = u.link
+            k = u.len
+            
+        return u
+    
+    def add(self, a):
+        
+        # We need to find the maximum suffix-palindrome P of Ta
+        # Start by finding maximum suffix-palindrome Q of T.
+        # To do this, we traverse the suffix-palindromes of T
+        # in the order of decreasing length, starting with maxSuf(T)
+        Q = self.get_max_suffix_pal(self.maxSufT, a)
+        
+        # We check Q to see whether it has an outgoing edge labeled by a.
+        createANewNode = not a in Q.edges
+        
+        if createANewNode:
+            # We create the node P of length Q+2
+            P = Eernode()
+            self.nodes.append(P)
+            P.len = Q.len + 2
+            if P.len == 1:
+                # if P = a, create the suffix link (P,0)
+                P.link = self.rte
+            else:
+                # It remains to create the suffix link from P if |P|>1. Just
+                # continue traversing suffix-palindromes of T starting with the suffix 
+                # link of Q.
+                P.link = self.get_max_suffix_pal(Q.link, a).edges[a]
+                
+            # create the edge (Q,P)
+            Q.edges[a] = P
+            
+        #P becomes the new maxSufT
+        self.maxSufT = Q.edges[a]
+        
+        #Store accumulated input string
+        self.S.append(a)
+        
+        return createANewNode
+    
+    def get_sub_palindromes(self, nd, nodesToHere, charsToHere, result):
+        #Each node represents a palindrome, which can be reconstructed
+        #by the path from the root node to each non-root node.
+            
+        #Traverse all edges, since they represent other palindromes
+        for lnkName in nd.edges:
+            nd2 = nd.edges[lnkName] #The lnkName is the character used for this edge
+            self.get_sub_palindromes(nd2, nodesToHere+[nd2], charsToHere+[lnkName], result)
+            
+        #Reconstruct based on charsToHere characters.
+        if id(nd) != id(self.rto) and id(nd) != id(self.rte): #Don't print for root nodes
+            tmp = "".join(charsToHere)
+            if id(nodesToHere[0]) == id(self.rte): #Even string
+                assembled = tmp[::-1] + tmp
+            else: #Odd string
+                assembled = tmp[::-1] + tmp[1:]
+            result.append(assembled)
+
+class TestEertree(unittest.TestCase):
+
+        def test_ex1(self):
+          self.assertEqual(eertree("redivider"),["r","redivider","e","edivide","d","divid","i","ivi","v"],'example 1')
+
+        def test_ex2(self):
+          self.assertEqual(eertree("deific"),["d","e","i","ifi","f","c"],'example 2')
+
+        def test_ex3(self):
+          self.assertEqual(eertree("rotors"),["r","rotor","o","oto","t","s"],'example 3')
+
+        def test_ex4(self):
+          self.assertEqual(eertree("challenge"),["c","h","a","l","ll","e","n","g"],'example 4')
+
+        def test_ex5(self):
+          self.assertEqual(eertree("champion"),["c","h","a","m","p","i","o","n"],'example 5')
+
+        def test_ex6(self):
+          self.assertEqual(eertree("christmas"),["c","h","r","i","s","t","m","a"],'example 6')
+
+unittest.main()