1 files changed, 43 insertions, 0 deletions
diff --git a/challenge-167/michael-dicicco/java/challenge167/task1.java b/challenge-167/michael-dicicco/java/challenge167/task1.java
new file mode 100644
index 0000000000..695304347a
--- /dev/null
+++ b/challenge-167/michael-dicicco/java/challenge167/task1.java
@@ -0,0 +1,43 @@
+/*
+ * Click nbfs://nbhost/SystemFileSystem/Templates/Licenses/license-default.txt to change this license
+ * Click nbfs://nbhost/SystemFileSystem/Templates/Classes/Main.java to edit this template
+ */
+package challenge167;
+
+/**
+ *
+ * @author mddicicco
+ */
+public class task1 {
+
+    /**
+     * Challenge 167 Task1
+     *
+     * Solution By: Michael DiCicco
+     *
+     * Write a script to find out first 10 circular primes having at least 3
+     * digits (base 10). Please checkout wikipedia for more information. A
+     * circular prime is a prime number with the property that the number
+     * generated at each intermediate step when cyclically permuting its (base
+     * 10) digits will also be prime.
+     *
+     * Output 113, 197, 199, 337, 1193, 3779, 11939, 19937, 193939, 199933
+     */
+    
+    public static void main(String[] args) {
+        String[] ten_circular_primes = new String[10];
+        String someNumber = "111";
+        int index = 0;
+        while (ten_circular_primes[9] == null) {
+            if (circularprime.validate(someNumber)) {
+                if (!circularprime.used_numbers.contains(someNumber)) {
+                    ten_circular_primes[index] = someNumber;
+                    index++;
+                }
+            }
+            someNumber = Integer.toString(Integer.parseInt(someNumber) + 1);
+        }
+        System.out.println(String.join(", ", ten_circular_primes));
+
+    }
+}