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diff --git a/challenge-206/spadacciniweb/python/ch-1.py b/challenge-206/spadacciniweb/python/ch-1.py
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+# Task 1: Shortest Time
+# Submitted by: Mohammad S Anwar
+# 
+# You are given a list of time points, at least 2, in the 24-hour clock format HH:MM.
+# Write a script to find out the shortest time in minutes between any two time points.
+#
+# Example 1
+# Input: @time = ("00:00", "23:55", "20:00")
+# Output: 5
+# 
+# Since the difference between "00:00" and "23:55" is the shortest (5 minutes).
+# 
+# Example 2
+# Input: @array = ("01:01", "00:50", "00:57")
+# Output: 4
+# 
+# Example 3
+# Input: @array = ("10:10", "09:30", "09:00", "09:55")
+# Output: 15
+
+import re
+import sys
+from itertools import combinations
+
+def get_minutes(t):
+    return 60 * int(t[0:2]) + int(t[3:5])
+
+def get_diff_minutes(m1, m2):
+    res = abs(m1-m2)
+
+    if (res >= 720):        # 12h * 60 = minutes
+        return 1440 - res   # 24h * 60 = minutes
+    return res
+
+if __name__ == "__main__":
+    input = sys.argv[1:]
+    if (len(input) < 2
+        or
+        len(list(filter(lambda x: re.search(r'\d\d:\d\d', x), input))) != len(input)
+        or
+        len(list(filter(lambda x: x > '24:00', input))) != 0 ):
+        sys.exit("Input error\n")
+
+    minutes = [get_minutes(x) for x in input]
+    comb = combinations(range(len(input)), 2)
+    h_minutes = {
+        'val': None,
+        'pair': None
+    }
+
+    for pair in list(comb):
+        diff_minutes = get_diff_minutes(minutes[pair[0]], minutes[pair[1]])
+        if h_minutes['val'] == None or h_minutes['val'] > diff_minutes:
+            h_minutes['val'] = diff_minutes
+            h_minutes['pair'] = pair
+    
+    print(h_minutes['val'])
+    print("Since the difference between \"{:s}\" and \"{:s}\" is the shortest ({:d} minutes).".format(input[ h_minutes['pair'][0] ], input[ h_minutes['pair'][1] ], h_minutes['val'] ))
diff --git a/challenge-206/spadacciniweb/python/ch-2.py b/challenge-206/spadacciniweb/python/ch-2.py
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+# Task 2: Array Pairings
+# Submitted by: Mohammad S Anwar
+# 
+# You are given an array of integers having even number of elements..
+# Write a script to find the maximum sum of the minimum of each pairs.
+# 
+# Example 1
+# Input: @array = (1,2,3,4)
+# Output: 4
+# 
+# Possible Pairings are as below:
+# a) (1,2) and (3,4). So min(1,2) + min(3,4) => 1 + 3 => 4
+# b) (1,3) and (2,4). So min(1,3) + min(2,4) => 1 + 2 => 3
+# c) (1,4) and (2,3). So min(1,4) + min(2,3) => 2 + 1 => 3
+# 
+# So the maxium sum is 4.
+# 
+# Example 2
+# Input: @array = (0,2,1,3)
+# Output: 2
+# 
+# Possible Pairings are as below:
+# a) (0,2) and (1,3). So min(0,2) + min(1,3) => 0 + 1 => 1
+# b) (0,1) and (2,3). So min(0,1) + min(2,3) => 0 + 2 => 2
+# c) (0,3) and (2,1). So min(0,3) + min(2,1) => 0 + 1 => 1
+# 
+# So the maximum sum is 2.
+import re
+import sys
+from functools import reduce
+
+# https://stackoverflow.com/questions/19368375/set-partitions-in-python
+def partition(collection):
+    if len(collection) == 1:
+        yield [ collection ]
+        return
+
+    first = collection[0]
+    for smaller in partition(collection[1:]):
+        # insert `first` in each of the subpartition's subsets
+        for n, subset in enumerate(smaller):
+            yield smaller[:n] + [[ first ] + subset]  + smaller[n+1:]
+        # put `first` in its own subset 
+        yield [ [ first ] ] + smaller
+
+
+
+if __name__ == "__main__":
+    input = sys.argv[1:]
+    if (len(input) < 2
+        or
+        len(input) % 2 != 0
+        or
+        len(list(filter(lambda x: re.search(r'\D', x), input))) != 0):
+        sys.exit("Input error\n")
+
+    input = list(map(int, input))
+    pairing = []
+    for n, p in enumerate(partition(input), 1):
+        sets = sorted(p)
+        b_pair = True
+        for s in sets:
+            if len(s) != 2:
+                b_pair = False
+                break
+        if b_pair == True:
+            pairing.append(sets)
+
+    l_min = []
+    for pairs in list(pairing):
+        l_min.append([min(s) for s in pairs])
+
+    print(max([sum(s) for s in l_min]))