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+/*
+Challenge 209
+
+Task 2: Merge Account
+Submitted by: Mohammad S Anwar
+
+You are given an array of accounts i.e. name with list of email addresses.
+
+Write a script to merge the accounts where possible. The accounts can only
+be merged if they have at least one email address in common.
+
+Example 1:
+
+Input: @accounts = [ ["A", "a1@a.com", "a2@a.com"],
+                     ["B", "b1@b.com"],
+                     ["A", "a3@a.com", "a1@a.com"] ]
+                   ]
+
+Output: [ ["A", "a1@a.com", "a2@a.com", "a3@a.com"],
+          ["B", "b1@b.com"] ]
+
+Example 2:
+
+Input: @accounts = [ ["A", "a1@a.com", "a2@a.com"],
+                     ["B", "b1@b.com"],
+                     ["A", "a3@a.com"],
+                     ["B", "b2@b.com", "b1@b.com"] ]
+
+Output: [ ["A", "a1@a.com", "a2@a.com"],
+          ["A", "a3@a.com"],
+          ["B", "b1@b.com", "b2@b.com"] ]
+*/
+
+#include <algorithm>
+#include <iostream>
+#include <string>
+#include <vector>
+
+struct Account {
+    std::string name;
+    std::vector<std::string> emails;
+
+    Account(const std::string& name_) : name(name_) {}
+
+    void merge(const Account& other) {
+        emails.insert(emails.end(), other.emails.begin(), other.emails.end());  // concatenate
+        std::sort(emails.begin(), emails.end());                                // sort
+        auto it = std::unique(emails.begin(), emails.end());                    // uniq
+        emails.resize(std::distance(emails.begin(), it));
+    }
+};
+
+bool find_common(std::vector<Account>& accs, size_t& a, size_t& b) {
+    for (a = 0; a < accs.size() - 1; a++) {
+        for (size_t i = 0; i < accs[a].emails.size(); i++) {
+            std::string& email = accs[a].emails[i];
+            for (b = a + 1; b < accs.size(); b++) {
+                auto it = std::find(accs[b].emails.begin(), accs[b].emails.end(), email);
+                if (it != accs[b].emails.end())
+                    return true;
+            }
+        }
+    }
+    return false;
+}
+
+void merge_accounts(std::vector<Account>& accs) {
+    size_t a, b;
+    while (find_common(accs, a, b)) {
+        accs[a].merge(accs[b]);
+        accs.erase(accs.begin() + b);
+    }
+}
+
+int main(int argc, char* argv[]) {
+    argv++; argc--;
+    if (argc == 0) {
+        std::cerr << "usage: ch-2 name emails... name emails..." << std::endl;
+        return EXIT_FAILURE;
+    }
+
+    std::vector<Account> accs;
+
+    for (int i = 0; i < argc; i++) {
+        std::string name = argv[i++];
+        accs.emplace_back(name);
+        for (; i < argc && std::string(argv[i])!= ","; i++) {
+            std::string email = argv[i];
+            accs.back().emails.push_back(email);
+        }
+    }
+
+    merge_accounts(accs);
+
+    for (size_t i = 0; i < accs.size(); i++) {
+        std::cout << accs[i].name << " ";
+        for (size_t j = 0; j < accs[i].emails.size(); j++)
+            std::cout << accs[i].emails[j] << " ";
+        std::cout << std::endl;
+    }
+}