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Diffstat (limited to 'challenge-245/lubos-kolouch/python/ch-2.py')
| -rw-r--r-- | challenge-245/lubos-kolouch/python/ch-2.py | 37 |
1 files changed, 37 insertions, 0 deletions
diff --git a/challenge-245/lubos-kolouch/python/ch-2.py b/challenge-245/lubos-kolouch/python/ch-2.py new file mode 100644 index 0000000000..f31c9a44e8 --- /dev/null +++ b/challenge-245/lubos-kolouch/python/ch-2.py @@ -0,0 +1,37 @@ +#!/usr/bin/env python + + +def largest_multiple_of_three(ints): + # Sort numbers in descending order + ints.sort(reverse=True) + + # Function to calculate the sum of digits + sum_digits = sum(ints) + + # Function to remove the smallest element with a specified remainder + def remove_smallest(remainder): + for i in range(len(ints) - 1, -1, -1): + if ints[i] % 3 == remainder: + del ints[i] + return True + return False + + # Adjust the list to make the sum of its digits divisible by 3 + if sum_digits % 3 == 1: + # Try to remove one number with a remainder of 1, else remove two with a remainder of 2 + if not remove_smallest(1): + remove_smallest(2) and remove_smallest(2) + elif sum_digits % 3 == 2: + # Try to remove one number with a remainder of 2, else remove two with a remainder of 1 + if not remove_smallest(2): + remove_smallest(1) and remove_smallest(1) + + return int("".join(map(str, ints))) if ints and sum(ints) % 3 == 0 else -1 + + +# Test Cases +test1 = largest_multiple_of_three([8, 1, 9]) == 981 +test2 = largest_multiple_of_three([8, 6, 7, 1, 0]) == 8760 +test3 = largest_multiple_of_three([1]) == -1 + +test1, test2, test3 |
