diff options
Diffstat (limited to 'challenge-247/pokgopun/python')
| -rw-r--r-- | challenge-247/pokgopun/python/ch-1.py | 122 | ||||
| -rw-r--r-- | challenge-247/pokgopun/python/ch-2.py | 65 |
2 files changed, 187 insertions, 0 deletions
diff --git a/challenge-247/pokgopun/python/ch-1.py b/challenge-247/pokgopun/python/ch-1.py new file mode 100644 index 0000000000..e85b8422c7 --- /dev/null +++ b/challenge-247/pokgopun/python/ch-1.py @@ -0,0 +1,122 @@ +### https://theweeklychallenge.org/blog/perl-weekly-challenge-247/ +""" + +Task 1: Secret Santa + +Submitted by: [54]Andreas Voegele + __________________________________________________________________ + + Secret Santa is a Christmas tradition in which members of a group are + randomly assigned a person to whom they give a gift. + + You are given a list of names. Write a script that tries to team + persons from different families. + +Example 1 + +The givers are randomly chosen but don't share family names with the receivers. + +Input: @names = ('Mr. Wall', + 'Mrs. Wall', + 'Mr. Anwar', + 'Mrs. Anwar', + 'Mr. Conway', + 'Mr. Cross', + ); + +Output: + + Mr. Conway -> Mr. Wall + Mr. Anwar -> Mrs. Wall + Mrs. Wall -> Mr. Anwar + Mr. Cross -> Mrs. Anwar + Mr. Wall -> Mr. Conway + Mrs. Anwar -> Mr. Cross + +Example 2 + +One gift is given to a family member. + +Input: @names = ('Mr. Wall', + 'Mrs. Wall', + 'Mr. Anwar', + ); + +Output: + + Mr. Anwar -> Mr. Wall + Mr. Wall -> Mrs. Wall + Mrs. Wall -> Mr. Anwar + +Task 2: Most Frequent Letter Pair +""" +### solution by pokgopun@gmail.com + +from random import sample + +def secretSanta(names: tuple): + fnames = list( (e.split(" ")[-1],e) for e in names ) + mx = None + for i in range(len(fnames)): + cnt = len(tuple(e for e in names if e.endswith(fnames[i][0]))) + if mx is None or mx < cnt: + mx = cnt + fnames[i] += (cnt,) + #fnames.sort(key=lambda x: (x[-1],x[0]),reverse=True) + l = len(fnames) + givers = list() + for i in range(l): + candidates = tuple(e[1] for e in fnames if e[0]!=fnames[i][0] and e[1] not in givers) + if len(candidates) == 0: + candidates = tuple(e[1] for e in fnames if e[1]!=fnames[i][1] and e[1] not in givers) + #print(candidates) + if i==l-2 and fnames[l-1][1] not in givers: + #print('arbitarily set giver to '+fnames[l-1][1]) + giver=fnames[l-1][1] + else: + giver = sample(candidates,k=1)[0] + givers.append(giver) + yield (giver,fnames[i][1]) + +import unittest + +class TestSecretSanta(unittest.TestCase): + def test1(self): + givers, takers = [],[] + names = ( + 'Mr. Wall', + 'Mrs. Wall', + 'Mr. Anwar', + 'Mrs. Anwar', + 'Mr. Conway', + 'Mr. Cross', + ) + result = "" + for giver,taker in secretSanta(names): + self.assertEqual(givers.count(giver), 0, f"giver {giver} has already been assigned") + givers.append(giver) + self.assertEqual(takers.count(taker), 0, f"taker {taker} has already been assigned") + takers.append(taker) + self.assertNotEqual(giver, taker, f"error: giver's name '{giver}' is equal to taker's name '{taker}'") + giverFam, takerFam = giver.split(" ")[-1], taker.split(" ")[-1] + self.assertNotEqual(giverFam, takerFam, f"error: giver's family '{giverFam}' is equal to taker's family '{takerFam}'") + result += f"{giver} -> {taker}\n" + print(f"\nInput: @name = {names}\nOutput:\n{result}") + def test2(self): + givers, takers = [],[] + names = ( + 'Mr. Wall', + 'Mrs. Wall', + 'Mr. Anwar', + ) + result = "" + for giver,taker in secretSanta(names): + self.assertEqual(givers.count(giver), 0, f"giver {giver} has already been assigned") + givers.append(giver) + self.assertEqual(takers.count(taker), 0, f"taker {taker} has already been assigned") + takers.append(taker) + self.assertNotEqual(giver, taker, f"error: giver's name '{giver}' is equal to taker's name '{taker}'") + result += f"{giver} -> {taker}\n" + print(f"\nInput: @name = {names}\nOutput:\n{result}") + +unittest.main() diff --git a/challenge-247/pokgopun/python/ch-2.py b/challenge-247/pokgopun/python/ch-2.py new file mode 100644 index 0000000000..54c77654be --- /dev/null +++ b/challenge-247/pokgopun/python/ch-2.py @@ -0,0 +1,65 @@ +### https://theweeklychallenge.org/blog/perl-weekly-challenge-247/ +""" + +Task 2: Most Frequent Letter Pair + +Submitted by: [55]Jorg Sommrey + __________________________________________________________________ + + You are given a string S of lower case letters 'a'..'z'. + + Write a script that finds the pair of consecutive letters in S that + appears most frequently. If there is more than one such pair, chose the + one that is the lexicographically first. + +Example 1 + +Input: $s = 'abcdbca' +Output: 'bc' + +'bc' appears twice in `$s` + +Example 2 + +Input: $s = 'cdeabeabfcdfabgcd' +Output: 'ab' + +'ab' and 'cd' both appear three times in $s and 'ab' is lexicographically smalle +r than 'cd'. + __________________________________________________________________ + + Last date to submit the solution 23:59 (UK Time) Sunday 17th December + 2023. + __________________________________________________________________ + +SO WHAT DO YOU THINK ? +""" +### solution by pokgopun@gmail.com + +def mflp(string: str): + l = len(string) + if l <= 2: + return "" + dct = dict() + for i in range(l-1): + pair = string[i:i+2] + if dct.get(pair) is None: + dct[pair] = 1 + else: + dct[pair] += 1 + lst = list((-dct[x],x) for x in dct.keys()) + lst.sort() + #print(lst) + return lst[0][1] + +import unittest + +class TestMflp(unittest.TestCase): + def test1(self): + for inpt, otpt in { + 'abcdbca': 'bc', + 'cdeabeabfcdfabgcd': 'ab', + }.items(): + self.assertEqual(mflp(inpt),otpt,f"error: most frequent letter pair of '{inpt}' must be '{otpt}'") + +unittest.main() |