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+#!/usr/bin/env python3
+
+# Challenge 286
+#
+# Task 2: Order Game
+# Submitted by: Mohammad Sajid Anwar
+#
+# You are given an array of integers, @ints, whose length is a power of 2.
+#
+# Write a script to play the order game (min and max) and return the last element.
+# Example 1
+#
+# Input: @ints = (2, 1, 4, 5, 6, 3, 0, 2)
+# Output: 1
+#
+# Operation 1:
+#
+#     min(2, 1) = 1
+#     max(4, 5) = 5
+#     min(6, 3) = 3
+#     max(0, 2) = 2
+#
+# Operation 2:
+#
+#     min(1, 5) = 1
+#     max(3, 2) = 3
+#
+# Operation 3:
+#
+#     min(1, 3) = 1
+#
+# Example 2
+#
+# Input: @ints = (0, 5, 3, 2)
+# Output: 0
+#
+# Operation 1:
+#
+#     min(0, 5) = 0
+#     max(3, 2) = 3
+#
+# Operation 2:
+#
+#     min(0, 3) = 0
+#
+# Example 3
+#
+# Input: @ints = (9, 2, 1, 4, 5, 6, 0, 7, 3, 1, 3, 5, 7, 9, 0, 8)
+# Output: 2
+#
+# Operation 1:
+#
+#     min(9, 2) = 2
+#     max(1, 4) = 4
+#     min(5, 6) = 5
+#     max(0, 7) = 7
+#     min(3, 1) = 1
+#     max(3, 5) = 5
+#     min(7, 9) = 7
+#     max(0, 8) = 8
+#
+# Operation 2:
+#
+#     min(2, 4) = 2
+#     max(5, 7) = 7
+#     min(1, 5) = 1
+#     max(7, 8) = 8
+#
+# Operation 3:
+#
+#     min(2, 7) = 2
+#     max(1, 8) = 8
+#
+# Operation 4:
+#
+#     min(2, 8) = 2
+
+import sys
+
+def reduce(nums):
+    out = []
+    while len(nums) > 0:
+        if len(nums) >= 2:
+            out.append(min(nums[0], nums[1]))
+        if len(nums) >= 4:
+            out.append(max(nums[2], nums[3]))
+        nums = nums[4:]
+    return out
+
+nums = list(map(int, sys.argv[1:]))
+while len(nums) > 1:
+    nums = reduce(nums)
+
+print(nums[0])