1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
|
As published on https://perlweeklychallenge.org/blog/a-new-week-a-new-challenge/ <br/>
Submissions demonstrated here using [Reply](https://metacpan.org/pod/Reply).
> Write a script to replace the character ‘e’ with ‘E’ in the string ‘Perl Weekly Challenge’. Also print the number of times the character ‘e’ is found in the string.
I didn't write a script so I fail this challenge already.
```
0> my $foo = 'Perl Weekly Challenge'
$res[0] = "Perl Weekly Challenge"
1> $foo =~ s/e/E/g;
$res[1] = 5
2> $foo
$res[2] = "PErl WEEkly ChallEngE"
3>
```
> Write a one-liner to solve the FizzBuzz problem and print the numbers 1 through 20. However, any number divisible by 3 should be replaced by the word ‘fizz’ and any divisible by 5 by the word ‘buzz’. Those numbers that are both divisible by 3 and 5 become ‘fizzbuzz’.
I don't remember where I saw this, but it is my favourite Perl5 FizzBuzz:
```
4> { no strict; no warnings; map { (fizz)[$_%3].(buzz)[$_%5]||$_ } 1..20 }
$res[4] = [
[0] 1,
[1] 2,
[2] "fizz",
[3] 4,
[4] "buzz",
[5] "fizz",
[6] 7,
[7] 8,
[8] "fizz",
[9] "buzz",
[10] 11,
[11] "fizz",
[12] 13,
[13] 14,
[14] "fizzbuzz",
[15] 16,
[16] 17,
[17] "fizz",
[18] 19,
[19] "buzz"
]
```
Since I didn't write that myself I also fail the second part of the challenge. Not going well. Let's see...
```
$ perl -MAcme::FizzBuzz -e '1' | head -n 20 | tr '[:upper:]' '[:lower:]'
1
2
fizz
4
buzz
fizz
7
8
fizz
buzz
11
fizz
13
14
fizzbuzz
16
17
fizz
19
buzz
```
There!
|
