1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
|
' Challenge 002
'
' Challenge #2
' Write a script that can convert integers to and from a base35
' representation, using the characters 0-9 and A-Y. Dave Jacoby came up
' with nice description about base35, in case you needed some background.
function format_digit(n as integer) as string
if n<10 then
format_digit = chr(n+asc("0"))
else
format_digit = chr(n+asc("A")-10)
end if
end function
function format_number(n as integer, radix as integer) as string
dim negative as boolean, text as string, d as integer
if n<0 then
negative = true
n = -n
end if
do
d = n mod radix
n = int(n / radix)
text = format_digit(d) & text
loop while n > 0
if negative then
text = "-" & text
end if
format_number = text
end function
function scan_digit(c as string) as integer
if c >= "0" and c < "9" then
scan_digit = asc(c)-asc("0")
elseif ucase(c) >= "A" and ucase(c) <= "Z" then
scan_digit = asc(ucase(c))-asc("A")+10
else
scan_digit = -1
end if
end function
function scan_number(text as string, radix as integer) as integer
dim negative as boolean, n as integer, i as integer, d as integer
if left(text,1) = "-" then
negative = true
text = mid(text, 2)
end if
for i=1 to len(text)
d = scan_digit(mid(text,i,1))
if d < 0 or d >= radix then
print "invalid number"
end
end if
n = n*radix + d
next i
if negative then
n = -n
end if
scan_number = n
end function
' main
if command(1) = "-r" then
print scan_number(command(2), 35)
else
print format_number(val(command(1)), 35)
end if
|
