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#!/usr/bin/env python3
###########################################################################
# script name: ch-2.py #
# #
# https://github.com/user-person #
# #
# https://perlweeklychallenge.org/blog/perl-weekly-challenge-052/ #
# #
# Lucky Winner #
# Suppose there are following coins arranged on a table in a line in #
# random order #
# #
# 1, 50p, 1p, 10p, 5p, 2, 2p #
# #
# Suppose you are playing against the computer. Player can only pick one #
# coin at a time from either ends. Find out the lucky winner, who has #
# the larger amounts in total?20p, order. #
# #
###########################################################################
# Coins total 3.88. 2 > 1.88 . If a player gets the L2 coin they win the game.
# Given sufficiently intelligent players, whoever gets the first turn wins the game.
import random
import readline
coins = [ '1p', '2p', '5p', '10p', '20p', '50p', 'L1', 'L2' ]
random.shuffle(coins)
coinVal = { '1p' : 0.01, '2p' : 0.02, '5p' : 0.05, '10p' : 0.10, \
'20p' : 0.20, '50p' : 0.50, 'L1' : 1.00, 'L2' : 2.00 }
bank = { 'player' : 0, 'computer' : 0 }
turn = random.choice([True,False])
def l2Index():
ret = -1
for i in range(len(coins)-1):
if coins[i] == 'L2':
ret = i
break
return ret
def takeCoin(choice,who):
if choice == 'f':
bank[who] += coinVal[ coins.pop(0) ]
else: # "If you ain't first, you're last."
bank[who] += coinVal[ coins.pop(-1) ]
print(who + ': ' + '{:.2f}'.format(bank[who]) + '\n')
def playerChoice():
fl = ''
loop = True
prompt = "Type 'f' to choose the first coin. Type 'l' to choose the last coin. Type 'q' to quit:" ;
if len(coins) > 1:
print(prompt)
while loop:
loop = False
if len(coins) == 1: # Don't ask when there's only one choice.
takeCoin( 'f', 'player')
continue
fl = input('> ')
if fl == 'f' or fl == 'l':
takeCoin( fl, 'player')
elif fl == 'q':
exit()
else:
print('Invalid choice')
loop = True
def chooseGreater():
if coinVal[ coins[0] ] > coinVal[ coins[-1] ] :
takeCoin('f','computer')
else:
takeCoin('l','computer')
def computerChoice():
# Grabs L2 off the end when available
# Doesn't grab the item before L2 to free it up for player to win.
# Otherwise, grabs whichever end is greater.
# It doesn't always get the highest points, but it wins when that's possible.
ind = l2Index()
if len(coins) == 3: # Without this statement computer always chooses last (third)
chooseGreater() # when protecting L2 ( e.g. [first], L2, [last] )
# even if first is greater.
else:
if ind == 0 or ind == len(coins)-2:
takeCoin('f','computer')
elif ind == len(coins)-1 or ind == 1:
takeCoin('l','computer')
else:
chooseGreater()
while len(coins):
for c in coins:
print(c,end=' ')
print()
if turn:
playerChoice()
turn = False
else:
computerChoice()
turn = True
if bank['computer'] > bank['player']:
print('Computer Wins. Computer: L ' + '{:.2f}'.format(bank['computer']) \
+ ' Player: L ' + '{:.2f}'.format(bank['player']) + '\n')
else:
print('Player Wins. Player: L ' + '{:.2f}'.format(bank['player']) \
+ ' Computer: L ' + '{:.2f}'.format(bank['computer']) + '\n')
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