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#!/usr/bin/env python3
# Challenge 058
#
# TASK #1 › Compare Version
# Reviewed by Ryan Thompson
# Compare two given version number strings v1 and v2 such that:
#
# If v1 > v2 return 1
# If v1 < v2 return -1
# Otherwise, return 0
# The version numbers are non-empty strings containing only digits, and the dot
# (“.”) and underscore (“_”) characters. (“_” denotes an alpha/development
# version, and has a lower precedence than a dot, “.”). Here are some examples:
#
# v1 v2 Result
# ------ ------ ------
# 0.1 < 1.1 -1
# 2.0 > 1.2 1
# 1.2 < 1.2_5 -1
# 1.2.1 > 1.2_1 1
# 1.2.1 = 1.2.1 0
# Version numbers may also contain leading zeros. You may handle these how you
# wish, as long as it’s consistent.
import re
import sys
def split_version(v):
m = re.search(r'^\d+', v)
if not m:
return False
else:
v_1 = int(m.group(0))
if len(m.group(0)) == len(v):
v_sep = ''
v_rest = ''
else:
v_sep = v[len(m.group(0))]
v_rest = v[len(m.group(0))+1:]
return True, v_1, v_sep, v_rest
def compare_version(a, b):
if a == b:
return 0
else:
a_ok, a_1, a_sep, a_rest = split_version(a)
b_ok, b_1, b_sep, b_rest = split_version(b)
if not a_ok or not b_ok:
return 0
elif a_1 < b_1:
return -1
elif a_1 > b_1:
return 1
elif a_sep == b_sep:
return compare_version(a_rest, b_rest)
elif a_sep == '':
return -1
elif b_sep == '':
return 1
elif a_sep == '.':
return -1
elif b_sep == '.':
return 1
else:
return compare_version(a_rest, b_rest)
a = sys.argv[1]
b = sys.argv[2]
print(compare_version(a,b))
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