1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
|
#!/usr/bin/env python
# Challenge 100
#
# TASK #2 > Triangle Sum
# Submitted by: Mohammad S Anwar
# You are given triangle array.
#
# Write a script to find the minimum path sum from top to bottom.
#
# When you are on index i on the current row then you may move to either
# index i or index i + 1 on the next row.
#
# Example 1:
# Input: Triangle = [ [1], [2,4], [6,4,9], [5,1,7,2] ]
# Output: 8
#
# Explanation: The given triangle
#
# 1
# 2 4
# 6 4 9
# 5 1 7 2
#
# The minimum path sum from top to bottom: 1 + 2 + 4 + 1 = 8
#
# [1]
# [2] 4
# 6 [4] 9
# 5 [1] 7 2
# Example 2:
# Input: Triangle = [ [3], [3,1], [5,2,3], [4,3,1,3] ]
# Output: 7
#
# Explanation: The given triangle
#
# 3
# 3 1
# 5 2 3
# 4 3 1 3
#
# The minimum path sum from top to bottom: 3 + 1 + 2 + 1 = 7
#
# [3]
# 3 [1]
# 5 [2] 3
# 4 3 [1] 3
import sys;
triangle = []
def add_row(row, items):
triangle.append(items)
def parse(args):
for i in range(0, len(args)):
items = [int(x) for x in args[i].split(",")]
add_row(i, items)
def min_sum():
def min_sum_1(sum, row, col):
sum += triangle[row][col]
if row+1 == len(triangle):
return sum
else:
sum1 = min_sum_1(sum, row+1, col)
sum2 = min_sum_1(sum, row+1, col+1)
return min(sum1, sum2)
return min_sum_1(0, 0, 0)
parse(sys.argv[1:])
print(min_sum())
|