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# Perl Weekly Challenge #120
You can find more information about this weeks, and previous weeks challenges at:
https://perlweeklychallenge.org/
If you are not already doing the challenge - it is a good place to practise your
**perl** or **raku**. If it is not **perl** or **raku** you develop in - you can
submit solutions in whichever language you feel comfortable with.
You can find the solutions here on github at:
https://github.com/drbaggy/perlweeklychallenge-club/tree/master/challenge-120/james-smith/perl
# Task 1 - Swap bits
***You are given a positive integer `$N` less than or equal to `255`. Write a script to swap the odd positioned bit with even positioned bit and print the decimal equivalent of the new binary representation.***
## The solution
This is very similar to last weeks challenge - but instead of swapping bits 4-7 with bits 0-3 this time we are swapping even bits with odd bits - so the solution is similar...
The even bits are found by bit-wise *and*ing the number with `0b01010101` 0r `0x55` (`85` decimal) and the odd bits are found by bit-wise anding with `0b10101010` or `0xaa` (`170` decimal). We then switch them by multiplying or dividing by 2 {which we do with the bit shift operators `<<` & `>>`}. We just have to add the two values together - as we know the bits don't overlap we can use `|` rather than `+`.
```perl
sub switch_bits {
($_[0]&0xaa)>>1 | ($_[0]&0x55)<<1;
}
```
# Task 2 - Clock Angle
***You are given time `$T` in the format `hh:mm`. Write a script to find the smaller angle formed by the hands of an analog clock at a given time.***
## The solution
Given a time we can compute the position of the hour hand as `$hr*30+$min/2` and the minute hand as `$min*6`.
We can then get the angle between the two as: `($hr*60+$min-$min*12)/2`
To make sure the angle is between `-360` and `360` we have to ensure that the hour is between `0` and `11`, by reducing it module 12. We then get the absolute value so we have a value between `0` and `360`
We need a number between `0` and `180`. To map the range `180` - `360` we can either use an IF OR we can note that if we
do `abs(angle - 180)` we get the complementary angle. So we just subtract this from `180` giving the method below...
```perl
sub clock_angle_1_liner {
180-abs(abs((substr$_[0],0,2)%12*30-5.5*substr$_[0],3)-180);
}
```
Compared to this (perhaps slightly more readable) method there is about a 85% performance gain [avoiding variables!]
```perl
sub clock_angle {
my($h,$m) = split /:/,shift;
my $t = abs($h%12*30-$m*5.5);
return $t > 180 ? 360-$t : $t;
}
```
**Note** We can gain more speed (110% faster than "simple" method and about 15% faster than the 1-liner) by removing the first `substr` but to do so we need to disable `numeric` warnings - `no warnings qw(numeric)`.
```perl
sub clock_angle_fast {
180-abs(abs($_[0]%12*30-5.5*substr$_[0],3)-180);
}
```
(Without disabling warnings this gives `Argument "04:00" isn't numeric in modulus (%) at ..` errors)
# Solutions in CESIL
OK - last weeks CESIL challenge was easier than this weeks....
Due to not having bit wise operations or an easy convert between hex and binary we have to find an alternative solution.
## Task 1
* In this case we work through the pairs of bits flipping them round.
* We compute the value of the bits by dividing though by 64 (then 16, 4, (and 1)) and taking the integer value.
* If the value is 0 or 3 then we do nothing otherwise we map 1 to 2 and 2 to 1 respectively....
* we repeat 4 times for each pair and keep a running sum which gives us our answer...
```
LINE
LOAD +0
STORE success
STORE tests
Next IN
JINEG End
STORE a
OUT
IN
STORE ans
LOAD +0
STORE res
LOAD +64
Loop STORE divisor
LOAD a
DIVIDE divisor
SUBTRACT 1
JIZERO j_1
SUBTRACT 1
JIZERO j_2
ADD 2
JUMP j
j_1 LOAD +2
JUMP j
j_2 LOAD +1
j MULTIPLY divisor
ADD res
STORE res
LOAD a
DIVIDE divisor
MULTIPLY divisor
MULTIPLY -1
ADD a
STORE a
LOAD divisor
DIVIDE +4
JIZERO EndL
JUMP Loop
EndL LOAD res
PRINT " => "
OUT
(Now run the test!
PRINT " : "
SUBTRACT ans
JIZERO Ok
PRINT "-- should be "
LOAD ans
OUT
PRINT "?"
JUMP Line
Ok PRINT "OK"
LOAD success
ADD +1
STORE success
Line LINE
LOAD tests
ADD +1
STORE tests
JUMP Next
End LINE
PRINT "TESTS: "
LOAD success
OUT
PRINT " of "
LOAD tests
OUT
PRINT " passed"
LINE
LINE
HALT
%
101
154
18
33
154
101
33
18
-1
```
Output...
```
101 => 154 : OK
18 => 33 : OK
154 => 101 : OK
33 => 18 : OK
TESTS: 4 of 4 passed
```
## Task 2
**CAVEAT:**
* Can't cope with "odd minutes" as this will lead to a fractional angle {and CESIL is integer only}
* Can't handle non-integer input - so the times have to be put in without the : so `03:30` is put in as `0330`
```
( Compute the angle between the hour and minute hand
( Input contains of pairs of hour.minute & answer so
( can check calculations are OK!
LINE
LOAD +0
STORE success
STORE tests
Next IN
JINEG End
STORE mn
DIVIDE 100
STORE hr
MULTIPLY -100
ADD mn
STORE mn
LOAD hr
SUBTRACT +10
JINEG bl1
JUMP bl1e
bl1 PRINT "0"
bl1e ADD +10
OUT
PRINT ":"
LOAD mn
SUBTRACT +10
JINEG bl2
JUMP bl2e
bl2 PRINT "0"
bl2e ADD +10
OUT
IN
STORE ans
LOAD mn
PRINT " => "
MULTIPLY -11
DIVIDE +2
STORE t
LOAD hr
SUBTRACT 12
JINEG lt12
JUMP gt12
lt12 ADD +12
gt12 MULTIPLY +30
ADD t
JINEG lt0
JUMP gt0
lt0 MULTIPLY -1
gt0 SUBTRACT +180
JINEG ltx0
MULTIPLY -1
ltx0 ADD +80
JINEG lt100
JUMP gt100
lt100 PRINT " "
ADD +90
JINEG lt10
JUMP gt10
lt10 PRINT " "
gt10 SUBTRACT +90
gt100 ADD +100
OUT
PRINT " : "
SUBTRACT ans
JIZERO Ok
PRINT "-- should be "
LOAD ans
OUT
PRINT "?"
JUMP Line
Ok PRINT "OK"
LOAD success
ADD +1
STORE success
Line LINE
LOAD tests
ADD +1
STORE tests
JUMP Next
End LINE
PRINT "TESTS: "
LOAD success
OUT
PRINT " of "
LOAD tests
OUT
PRINT " passed"
LINE
LINE
HALT
%
0318
9
0420
10
0440
100
0310
35
0400
120
0800
120
1600
120
1800
180
2000
120
-1
```
Output:
```
03:18 => 9 : OK
04:20 => 10 : OK
04:40 => 100 : OK
03:10 => 35 : OK
04:00 => 120 : OK
08:00 => 120 : OK
16:00 => 120 : OK
18:00 => 180 : OK
20:00 => 120 : OK
TESTS: 9 of 9 passed
```
## Aside CESIL interpreter v2
I do have an uncompressed version of this - but this was a challenge to get the
CESIL interpreter into 1K of Perl - partly as we are harking back to the days of
very small memory computers {about the time that I was programming a ZX81 with 1K
RAM and a 4K ROM}...
This fixes a few of the shortcomings in the interpreter last week {e.g. adds the
ability to add "comments" and handles both specs of positive constants}
```perl
#!/bin/perl
use strict;use warnings;my($M,$p,$r,@i,%m,@c,%q)=(1e6,0,0);
my@t=('PROGRAM REQUIRES MORE DATA','UNKNOWN VARIABLE ',
'DIVISION BY ZERO ','UNKNOWN LABEL ');
sub _e{die sprintf "\n*** %s%s *** %s \@ %d\n",$t[$_[0]],@{$c[$p]}[1,0],1+$p}
sub _j{exists$q{$_}?($p=$q{$_}-1):_e 3}
sub _v{/^[-+]?\d+$/?(0+$_):exists$m{$_}?$m{$_}:_e 1}
my%c=('LINE',sub{print"\n"},'OUT',sub{print$r},'STORE',sub{$m{$_}=$r},
'PRINT',sub{print s/^"//r=~s/"$//r},'IN',sub{@i?($r=shift@i):_e 0},
'JINEG',sub{_j if$r<0},'SUBTRACT',sub{$r-=_v},'MULTIPLY',sub{$r*=_v},
'ADD',sub{$r+=_v},'DIVIDE',sub{$_=_v;$r=$_?int($r/$_):_e 2},
'LOAD',sub{$r=_v},'JIZERO',sub{_j if!$r},'JUMP',sub{_j},'HALT',sub{exit});
while(<>){next if/^ *\(/;((@i=map{/^\s+[-+]?\d+\s*$/?0+$_:()}<>),last)if/^ *%/;
($q{$1},$_)=(0+@c,$2)if/^(\S{1,6})\s+(.*)/;
my($x,$y)=split/\s+/,s/^\s+//r=~s/\s+$//r,2;next unless $x;
die"\n# Unk cmd [$x \@ ",1+@c,"]\n"if!exists$c{$x};push@c,[$x,$y//''];}
($c{$c[$p][0]}($_=$c[$p][1]),$p++)while--$M&&$p<@c;
die"\n*** No HALT ***\n"
```
|