1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
|
#!/usr/bin/python3
# https://theweeklychallenge.org/blog/perl-weekly-challenge-244/#TASK1
#
# Task 1: Count Smaller
# =====================
#
# You are given an array of integers.
#
# Write a script to calculate the number of integers smaller than the integer
# at each index.
#
## Example 1
##
## Input: @int = (8, 1, 2, 2, 3)
## Output: (4, 0, 1, 1, 3)
##
## For index = 0, count of elements less 8 is 4.
## For index = 1, count of elements less 1 is 0.
## For index = 2, count of elements less 2 is 1.
## For index = 3, count of elements less 2 is 1.
## For index = 4, count of elements less 3 is 3.
#
## Example 2
##
## Input: @int = (6, 5, 4, 8)
## Output: (2, 1, 0, 3)
#
## Example 3
##
## Input: @int = (2, 2, 2)
## Output: (0, 0, 0)
#
############################################################
##
## discussion
##
############################################################
#
# Straight forward, for each element of the array, walk the whole array,
# checking each element for its size compared to the current one.
def count_smaller(ints: list):
result = []
print("Input: (", ", ".join(str(x) for x in ints), ")")
for elem in ints:
smaller = 0
for elem2 in ints:
if elem2 < elem:
smaller += 1
result.append(smaller)
print("Output: (", ", ".join(str(x) for x in result), ")")
count_smaller([ 8, 1, 2, 2, 3 ]);
count_smaller([ 6, 5, 4, 8 ]);
count_smaller([ 2, 2, 2 ]);
|
