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#!/usr/bin/env python
import re
from collections import Counter
def frequentWord(p, w):
# first, remove punctuation from the paragraph
# (but we'll leave apostrophes for contractions)
p = re.sub(r'[^a-z\'\s]', '', p.lower())
# count the words in $paragraph
count = Counter()
for pw in p.split():
count[pw] += 1
# generate the output about the banned word
bannedCount = count[w] if w in count else 0
output = f'The banned word "{w}" occurs {bannedCount} ';
output += 'time' if bannedCount == 1 else 'times'
output += ".\n"
# delete the banned word from the word count
del count[w]
# now find the most frequent word left and report on that
decorated = [ ( count[w], w ) for w in count.keys() ]
sorted_tuples = sorted(
decorated,
# the - before the first element sorts descending
key=lambda k: -k[0]
)
freqWord = sorted_tuples[0][1]
freqCount = count[freqWord]
output += f'The other word "{freqWord}" '
output += f'occurs {freqCount} '
output += 'time.' if freqCount == 1 else 'times.'
return (freqWord, output)
def solution(p, w):
print(f'Input: $p = "{p}"')
print(f' $w = "{w}"')
(freqWord, output) = frequentWord(p, w)
print(f'Output: "{freqWord}"')
print('')
print(output)
print('Example 1:')
solution(
"Joe hit a ball, the hit ball flew far after it was hit.",
"hit"
)
print('\nExample 2:')
solution(
"Perl and Raku belong to the same family. Perl is the most popular language in the weekly challenge.",
"the"
)
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