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#!/usr/bin/python3
# https://theweeklychallenge.org/blog/perl-weekly-challenge-257/#TASK1
#
# Task 1: Smaller than Current
# ============================
#
# You are given a array of integers, @ints.
#
# Write a script to find out how many integers are smaller than current i.e.
# foreach ints[i], count ints[j] < ints[i] where i != j.
#
## Example 1
##
## Input: @ints = (5, 2, 1, 6)
## Output: (2, 1, 0, 3)
##
## For $ints[0] = 5, there are two integers (2,1) smaller than 5.
## For $ints[1] = 2, there is one integer (1) smaller than 2.
## For $ints[2] = 1, there is none integer smaller than 1.
## For $ints[3] = 6, there are three integers (5,2,1) smaller than 6.
#
## Example 2
##
## Input: @ints = (1, 2, 0, 3)
## Output: (1, 2, 0, 3)
#
## Example 3
##
## Input: @ints = (0, 1)
## Output: (0, 1)
#
## Example 4
##
## Input: @ints = (9, 4, 9, 2)
## Output: (2, 1, 2, 0)
#
############################################################
##
## discussion
##
############################################################
#
# Walk through the array, and for each element, walk through
# the whole array again, counting the elements that are smaller
# than the one in the outer loop. Put the result of this loop run
# at the end of the final result.
#
def smaller_than_current(ints: list) -> None:
print("Input: (", ", ".join(str(x) for x in ints), ")", sep="")
result = []
for i in range(len(ints)):
count = 0
for j in range(len(ints)):
if i != j and ints[i] > ints[j]:
count += 1
result.append(count)
print("Output: (", ", ".join(str(x) for x in result), ")", sep="")
smaller_than_current([5, 2, 1, 6]);
smaller_than_current([1, 2, 0, 3]);
smaller_than_current([0, 1]);
smaller_than_current([9, 4, 9, 2]);
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