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#!/usr/bin/env perl
# vim:set ts=4 sw=4 sts=4 et ai wm=0 nu:
#=============================================================================
# Copyright (c) 2024, Bob Lied
#=============================================================================
#
# ch-1.pl Perl Weekly Challenge 259 Task 1 Banking Day Offset
#=============================================================================
# You are given a start date and offset counter. Optionally you also get bank
# holiday date list. Given a number (of days) and a start date, return the
# number (of days) adjusted to take into account non-banking days. In other
# words: convert a banking day offset to a calendar day offset.
# Non-banking days are: a) Weekends b) Bank holidays
# Example 1
# Input: $start_date = '2018-06-28', $offset = 3, $bank_holidays = ['2018-07-03']
# Output: '2018-07-04'
# Thursday bumped to Wednesday (3 day offset, with Monday a bank holiday)
# Example 2
# Input: $start_date = '2018-06-28', $offset = 3
# Output: '2018-07-03'
#=============================================================================
#=============================================================================
use v5.38;
use builtin qw/true false/; no warnings "experimental::builtin";
use Getopt::Long;
my $Verbose = 0;
my $DoTest = 0;
GetOptions("test" => \$DoTest, "verbose" => \$Verbose);
exit(!runTest()) if $DoTest;
sub bdo($startDate, $offset, $holiday = [])
{
use DateTime::Format::ISO8601;
my $day = DateTime::Format::ISO8601->parse_datetime($startDate);
# Convert holday list into a hash for easy lookup
my %bh = map { $_ => 1 } $holiday->@*;
while ( $offset > 0 )
{
$day->add(days => 1);
$offset-- if ! ( $day->day_of_week == 6
|| $day->day_of_week == 7
|| $bh{$day->ymd}
);
}
return $day->ymd;
}
sub runTest
{
use Test2::V0;
is( bdo('2018-06-28', 3, ['2018-07-03'] ), '2018-07-04', "Example 1");
is( bdo('2018-06-28', 3 ), '2018-07-03', "Example 1");
done_testing;
}
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