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#!/usr/bin/python3
# https://theweeklychallenge.org/blog/perl-weekly-challenge-261/#TASK1
#
# Task 1: Element Digit Sum
# =========================
#
# You are given an array of integers, @ints.
#
# Write a script to evaluate the absolute difference between element and digit
# sum of the given array.
#
## Example 1
##
## Input: @ints = (1,2,3,45)
## Output: 36
##
## Element Sum: 1 + 2 + 3 + 45 = 51
## Digit Sum: 1 + 2 + 3 + 4 + 5 = 15
## Absolute Difference: | 51 - 15 | = 36
#
## Example 2
##
## Input: @ints = (1,12,3)
## Output: 9
##
## Element Sum: 1 + 12 + 3 = 16
## Digit Sum: 1 + 1 + 2 + 3 = 7
## Absolute Difference: | 16 - 7 | = 9
#
## Example 3
##
## Input: @ints = (1,2,3,4)
## Output: 0
##
## Element Sum: 1 + 2 + 3 + 4 = 10
## Digit Sum: 1 + 2 + 3 + 4 = 10
## Absolute Difference: | 10 - 10 | = 0
#
## Example 4
##
## Input: @ints = (236, 416, 336, 350)
## Output: 1296
#
############################################################
##
## discussion
##
############################################################
#
# This is pretty straight forward, calculate the sum for each
# list, then calculate the digit sum by splitting each list
# element into its digits and then calculating the sum from there.
def element_digit_sum(ints: list) -> None:
print("Input: (", ", ".join(str(x) for x in ints), ")", sep="")
elem_sum = sum(ints)
digit_sum = 0
for elem in ints:
digits = [ int(x) for x in list(str(elem)) ]
digit_sum += sum(digits)
print("Output:", abs(elem_sum - digit_sum))
element_digit_sum([1,2,3,45]);
element_digit_sum([1,12,3]);
element_digit_sum([1,2,3,4]);
element_digit_sum([236, 416, 336, 350]);
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