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#!/usr/bin/python3
# https://theweeklychallenge.org/blog/perl-weekly-challenge-262/#TASK2
#
# Task 2: Count Equal Divisible
# =============================
#
# You are given an array of integers, @ints and an integer $k.
#
# Write a script to return the number of pairs (i, j) where
#
# a) 0 <= i < j < size of @ints
# b) ints[i] == ints[j]
# c) i x j is divisible by k
#
## Example 1
##
## Input: @ints = (3,1,2,2,2,1,3) and $k = 2
## Output: 4
##
## (0, 6) => ints[0] == ints[6] and 0 x 6 is divisible by 2
## (2, 3) => ints[2] == ints[3] and 2 x 3 is divisible by 2
## (2, 4) => ints[2] == ints[4] and 2 x 4 is divisible by 2
## (3, 4) => ints[3] == ints[4] and 3 x 4 is divisible by 2
#
## Example 2
##
## Input: @ints = (1,2,3) and $k = 1
## Output: 0
#
############################################################
##
## discussion
##
############################################################
#
# Have one index variable go from 0 to size of @ints - 1, then
# another walk from the first index + 1 to size of @ints - 1. In
# case ints[i] == ints[j], check if the product of i and j is
# divisible by $k. Return the sum of all instances where this is true.
def count_equal_divisible(ints: list, k: int) -> None:
print("Input: (", ", ".join(str(x) for x in ints), ")", sep="")
result = 0
for i in range(len(ints)):
for j in range(i+1, len(ints)):
if ints[i] == ints[j]:
if i * j % k == 0:
result += 1
print(f"Output: {result}")
count_equal_divisible( [3,1,2,2,2,1,3], 2);
count_equal_divisible( [1,2,3], 1);
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