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author冯昶 <seaker@qq.com>2021-03-15 18:13:51 +0800
committer冯昶 <seaker@qq.com>2021-03-15 18:13:51 +0800
commit8b6be37fe4dac8b4c6489a95e55514b76b298d15 (patch)
treeae36c8ec2c71f606c0e36adaa19dba366a68a0b4 /challenge-101/abigail/lua/ch-2.lua
parent865acfd056fb6f409ec6b1a81d60b931cbcb69fe (diff)
parentc9aec2da6bcb04b488183f09ca94bee488557aff (diff)
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Merge branch 'master' of github.com:seaker/perlweeklychallenge-club
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+#!/opt/local/bin/lua
+
+--
+-- See ../README.md
+--
+
+--
+-- Run as: lua ch-2.lua < input-file
+--
+
+--
+-- See ../README.md
+--
+
+--
+-- This determines on which side of the line through (x1, y1) and
+-- (x2, y2) the origin lies. If > 0, then the origin lies to the left
+-- of the line, if < 0, the origin lies to the right of the line, if
+-- = 0, the origin lies on the line.
+--
+function side (x1, y1, x2, y2)
+ return (y2 - y1) * x2 - (x2 - x1) * y2
+end
+
+for line in io . lines () do
+ --
+ -- Parse input
+ --
+ local _, _, x1, y1, x2, y2, x3, y3 =
+ line : find ("(%S+) (%S+) (%S+) (%S+) (%S+) (%S+)")
+
+ --
+ -- Determine where the origin is relative to the three lines
+ -- through the vertices of the triangle. Note we have to go
+ -- in a specific order through the points. (Either clock wise,
+ -- or counter clockwise, as long as we're consistent).
+ --
+ local s1 = side (x2, y2, x3, y3)
+ local s2 = side (x3, y3, x1, y1)
+ local s3 = side (x1, y1, x2, y2)
+
+ --
+ -- If the origin either lies to the left (or on) each of the
+ -- lines, or to the right (or on) each of the lines, the origin
+ -- lies inside the triangle. If not, it does not.
+ --
+ if (s1 <= 0 and s2 <= 0 and s3 <= 0) or
+ (s1 >= 0 and s2 >= 0 and s3 >= 0)
+ then print (1)
+ else print (0)
+ end
+end