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| author | 冯昶 <seaker@qq.com> | 2021-03-15 18:13:51 +0800 |
|---|---|---|
| committer | 冯昶 <seaker@qq.com> | 2021-03-15 18:13:51 +0800 |
| commit | 8b6be37fe4dac8b4c6489a95e55514b76b298d15 (patch) | |
| tree | ae36c8ec2c71f606c0e36adaa19dba366a68a0b4 /challenge-101/abigail/lua/ch-2.lua | |
| parent | 865acfd056fb6f409ec6b1a81d60b931cbcb69fe (diff) | |
| parent | c9aec2da6bcb04b488183f09ca94bee488557aff (diff) | |
| download | perlweeklychallenge-club-8b6be37fe4dac8b4c6489a95e55514b76b298d15.tar.gz perlweeklychallenge-club-8b6be37fe4dac8b4c6489a95e55514b76b298d15.tar.bz2 perlweeklychallenge-club-8b6be37fe4dac8b4c6489a95e55514b76b298d15.zip | |
Merge branch 'master' of github.com:seaker/perlweeklychallenge-club
Diffstat (limited to 'challenge-101/abigail/lua/ch-2.lua')
| -rw-r--r-- | challenge-101/abigail/lua/ch-2.lua | 52 |
1 files changed, 52 insertions, 0 deletions
diff --git a/challenge-101/abigail/lua/ch-2.lua b/challenge-101/abigail/lua/ch-2.lua new file mode 100644 index 0000000000..d7ecaacfb9 --- /dev/null +++ b/challenge-101/abigail/lua/ch-2.lua @@ -0,0 +1,52 @@ +#!/opt/local/bin/lua + +-- +-- See ../README.md +-- + +-- +-- Run as: lua ch-2.lua < input-file +-- + +-- +-- See ../README.md +-- + +-- +-- This determines on which side of the line through (x1, y1) and +-- (x2, y2) the origin lies. If > 0, then the origin lies to the left +-- of the line, if < 0, the origin lies to the right of the line, if +-- = 0, the origin lies on the line. +-- +function side (x1, y1, x2, y2) + return (y2 - y1) * x2 - (x2 - x1) * y2 +end + +for line in io . lines () do + -- + -- Parse input + -- + local _, _, x1, y1, x2, y2, x3, y3 = + line : find ("(%S+) (%S+) (%S+) (%S+) (%S+) (%S+)") + + -- + -- Determine where the origin is relative to the three lines + -- through the vertices of the triangle. Note we have to go + -- in a specific order through the points. (Either clock wise, + -- or counter clockwise, as long as we're consistent). + -- + local s1 = side (x2, y2, x3, y3) + local s2 = side (x3, y3, x1, y1) + local s3 = side (x1, y1, x2, y2) + + -- + -- If the origin either lies to the left (or on) each of the + -- lines, or to the right (or on) each of the lines, the origin + -- lies inside the triangle. If not, it does not. + -- + if (s1 <= 0 and s2 <= 0 and s3 <= 0) or + (s1 >= 0 and s2 >= 0 and s3 >= 0) + then print (1) + else print (0) + end +end |
