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| author | Paulo Custodio <pauloscustodio@gmail.com> | 2024-10-22 18:11:56 +0100 |
|---|---|---|
| committer | Paulo Custodio <pauloscustodio@gmail.com> | 2024-10-22 18:11:56 +0100 |
| commit | 45c413ded143a3d7548e837e2cc459f4fabcda41 (patch) | |
| tree | b82f0097d81f98326854e90cddbfaa9ff9613c15 /challenge-178/paulo-custodio/python/ch-2.py | |
| parent | c3edc9149c2c1d435eecf347139ca83094e1d86e (diff) | |
| download | perlweeklychallenge-club-45c413ded143a3d7548e837e2cc459f4fabcda41.tar.gz perlweeklychallenge-club-45c413ded143a3d7548e837e2cc459f4fabcda41.tar.bz2 perlweeklychallenge-club-45c413ded143a3d7548e837e2cc459f4fabcda41.zip | |
Add Python solutions
Diffstat (limited to 'challenge-178/paulo-custodio/python/ch-2.py')
| -rw-r--r-- | challenge-178/paulo-custodio/python/ch-2.py | 46 |
1 files changed, 46 insertions, 0 deletions
diff --git a/challenge-178/paulo-custodio/python/ch-2.py b/challenge-178/paulo-custodio/python/ch-2.py new file mode 100644 index 0000000000..e05c344ec8 --- /dev/null +++ b/challenge-178/paulo-custodio/python/ch-2.py @@ -0,0 +1,46 @@ +#!/usr/bin/env python3 + +# Challenge 178 +# +# Task 2: Business Date +# Submitted by: Mohammad S Anwar +# +# You are given $timestamp (date with time) and $duration in hours. +# +# Write a script to find the time that occurs $duration business hours after +# $timestamp. For the sake of this task, let us assume the working hours is 9am +# to 6pm, Monday to Friday. Please ignore timezone too. +# +# For example, +# +# Suppose the given timestamp is 2022-08-01 10:30 and the duration is 4 hours. +# Then the next business date would be 2022-08-01 14:30. +# +# Similar if the given timestamp is 2022-08-01 17:00 and the duration is 3.5 hours. +# Then the next business date would be 2022-08-02 11:30. + +from datetime import datetime, timedelta +import sys + +def next_business_date(date_text, time_text, hours): + date_str = f"{date_text} {time_text}" + date = datetime.strptime(date_str, "%Y-%m-%d %H:%M") + + minutes = hours * 60 + while True: + end_day = date.replace(hour=18, minute=0) + remain = (end_day - date).total_seconds() / 60 + if minutes < remain: + date += timedelta(minutes=minutes) + return date + else: + minutes -= remain + date = end_day + timedelta(hours=(24 - 18) + 9) + while date.weekday() >= 5: # skip weekend + date += timedelta(days=1) + +if len(sys.argv) != 4: + raise ValueError("usage: ch-2.py yyyy-mm-dd HH:MM hours") + +result_date = next_business_date(sys.argv[1], sys.argv[2], float(sys.argv[3])) +print(result_date.strftime("%Y-%m-%d %H:%M")) |
