feat(challenge-245/lubos-kolouch/perl,python,raku,blog): Challenge 245 LK Perl Python Raku blog

2 files changed, 64 insertions, 0 deletions

diff --git a/challenge-245/lubos-kolouch/python/ch-1.py b/challenge-245/lubos-kolouch/python/ch-1.py
new file mode 100644
index 0000000000..d960e4b918
--- /dev/null
+++ b/challenge-245/lubos-kolouch/python/ch-1.py
@@ -0,0 +1,27 @@
+#!/usr/bin/env python
+
+import unittest
+from typing import List, Tuple
+
+
+def sort_language(langs: list[str], popularity: list[int]) -> list[str]:
+    combined = sorted(zip(langs, popularity), key=lambda x: x[1])
+    return [lang for lang, _ in combined]
+
+
+# Test Cases
+class TestSortLanguage(unittest.TestCase):
+    def test_example_1(self):
+        self.assertEqual(
+            sort_language(["perl", "c", "python"], [2, 1, 3]), ["c", "perl", "python"]
+        )
+
+    def test_example_2(self):
+        self.assertEqual(
+            sort_language(["c++", "haskell", "java"], [1, 3, 2]),
+            ["c++", "java", "haskell"],
+        )
+
+
+if __name__ == "__main__":
+    unittest.main()
diff --git a/challenge-245/lubos-kolouch/python/ch-2.py b/challenge-245/lubos-kolouch/python/ch-2.py
new file mode 100644
index 0000000000..f31c9a44e8
--- /dev/null
+++ b/challenge-245/lubos-kolouch/python/ch-2.py
@@ -0,0 +1,37 @@
+#!/usr/bin/env python
+
+
+def largest_multiple_of_three(ints):
+    # Sort numbers in descending order
+    ints.sort(reverse=True)
+
+    # Function to calculate the sum of digits
+    sum_digits = sum(ints)
+
+    # Function to remove the smallest element with a specified remainder
+    def remove_smallest(remainder):
+        for i in range(len(ints) - 1, -1, -1):
+            if ints[i] % 3 == remainder:
+                del ints[i]
+                return True
+        return False
+
+    # Adjust the list to make the sum of its digits divisible by 3
+    if sum_digits % 3 == 1:
+        # Try to remove one number with a remainder of 1, else remove two with a remainder of 2
+        if not remove_smallest(1):
+            remove_smallest(2) and remove_smallest(2)
+    elif sum_digits % 3 == 2:
+        # Try to remove one number with a remainder of 2, else remove two with a remainder of 1
+        if not remove_smallest(2):
+            remove_smallest(1) and remove_smallest(1)
+
+    return int("".join(map(str, ints))) if ints and sum(ints) % 3 == 0 else -1
+
+
+# Test Cases
+test1 = largest_multiple_of_three([8, 1, 9]) == 981
+test2 = largest_multiple_of_three([8, 6, 7, 1, 0]) == 8760
+test3 = largest_multiple_of_three([1]) == -1
+
+test1, test2, test3